[R-meta] Difference in Proportions Meta-Analysis

[ne gic]

Dear Wolfgang,

Thank you!

Sincerely,
nelly

On Mon, Jun 8, 2020 at 12:42 PM Viechtbauer, Wolfgang (SP) <
wolfgang.viechtbauer using maastrichtuniversity.nl> wrote:

> Dear Nelly,
>
> For two independent estimates, y1 and y2, with standard errors SE1 and
> SE2, the SE of their difference is:
>
> SE[y1 - y2] = sqrt(SE1^2 + SE2^2)
>
> Best,
> Wolfgang
>
> >-----Original Message-----
> >From: R-sig-meta-analysis [mailto:
> r-sig-meta-analysis-bounces using r-project.org]
> >On Behalf Of ne gic
> >Sent: Monday, 08 June, 2020 12:37
> >To: r-sig-meta-analysis using r-project.org
> >Subject: [R-meta] Difference in Proportions Meta-Analysis
> >
> >Dear List,
> >
> >I aim to perform a meta-analysis and present a forest plot of the
> >difference in proportions between two groups.
> >
> >For each group I have proportion and standard error (SE).
> >
> >It's straightforward to get the difference in the proportions, but am not
> >sure how to handle the SEs, I presume I can't just subtract them. Is there
> >a formula on how to handle SEs?
> >
> >Sincerely,
> >nelly
>

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