[R-meta] Difference in Proportions Meta-Analysis
Viechtbauer, Wolfgang (SP)
wo||g@ng@v|echtb@uer @end|ng |rom m@@@tr|chtun|ver@|ty@n|
Mon Jun 8 12:41:41 CEST 2020
For two independent estimates, y1 and y2, with standard errors SE1 and SE2, the SE of their difference is:
SE[y1 - y2] = sqrt(SE1^2 + SE2^2)
>From: R-sig-meta-analysis [mailto:r-sig-meta-analysis-bounces using r-project.org]
>On Behalf Of ne gic
>Sent: Monday, 08 June, 2020 12:37
>To: r-sig-meta-analysis using r-project.org
>Subject: [R-meta] Difference in Proportions Meta-Analysis
>I aim to perform a meta-analysis and present a forest plot of the
>difference in proportions between two groups.
>For each group I have proportion and standard error (SE).
>It's straightforward to get the difference in the proportions, but am not
>sure how to handle the SEs, I presume I can't just subtract them. Is there
>a formula on how to handle SEs?
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