[R] Dplyr question

[John Fox]

Dear Thomas,

As others have noted, it's not obvious why one needs to use dplyr. 
Here's a solution in base R (with your original data in D):

 > D1 <- cbind(Location="P1A0B0D", D[, 1:2])
 > D2 <- cbind(Location="P190.90D", D[, c(1, 3)])
 > colnames(D1)[3] <- colnames(D2)[3] <- "Measurement"
 > rbind(D1[, c(2, 1, 3)], D2[, c(2, 1, 3)])
      Time_stamp Location Measurement
1  Jun-10 10:34  P1A0B0D   -0.000208
2  Jun-10 10:51  P1A0B0D   -0.000228
3  Jun-10 11:02  P1A0B0D   -0.000234
4  Jun-10 11:17  P1A0B0D   -0.000220
5  Jun-10 11:25  P1A0B0D   -0.000238
6  Jun-10 10:34 P190.90D   -0.000195
7  Jun-10 10:51 P190.90D   -0.000188
8  Jun-10 11:02 P190.90D   -0.000204
9  Jun-10 11:17 P190.90D   -0.000205
10 Jun-10 11:25 P190.90D   -0.000195

It would be simple to generalize this as a function.

I hope this helps,
  John

On 2022-06-21 12:22 p.m., Thomas Subia wrote:
> Colleagues:
> 
> The header of my data set is:
> Time_stamp	P1A0B0D	P190-90D
> Jun-10 10:34	-0.000208	-0.000195
> Jun-10 10:51	-0.000228	-0.000188
> Jun-10 11:02	-0.000234	-0.000204
> Jun-10 11:17	-0.00022	-0.000205
> Jun-10 11:25	-0.000238	-0.000195
> 
> I want my data set to resemble:
> 
> Time_stamp	Location	Measurement
> Jun-10 10:34	P1A0B0D	-0.000208
> Jun-10 10:51	P1A0B0D	-0.000228
> Jun-10 11:02	P1A0B0D	-0.000234
> Jun-10 11:17	P1A0B0D	-0.00022
> Jun-10 11:25	P1A0B0D	-0.000238
> Jun-10 10:34	P190-90D	-0.000195
> Jun-10 10:51	P190-90D	-0.000188
> Jun-10 11:02	P190-90D	-0.000204
> Jun-10 11:17	P190-90D	-0.000205
> Jun-10 11:25	P190-90D	-0.000195
> 
> I need some advice on how to do this using dplyr.
> 
> V/R
> Thomas Subia
> 
> FM Industries, Inc. - NGK Electronics, USA | www.fmindustries.com
> 221 Warren Ave, Fremont, CA 94539
> 
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> 
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-- 
John Fox, Professor Emeritus
McMaster University
Hamilton, Ontario, Canada
web: https://socialsciences.mcmaster.ca/jfox/