[R] Dplyr question

[Jeff Newmiller]

Beware of being too specific about how you want something solved... not just here, but in all contexts. Your question is like "how do I slice this apple with this potholder"... dplyr actually doesn't do that, and you can benefit from learning how to do things in general, not just in your preferred idiom.

ans <- 
do.call( rbind
       , lapply( names(dta[ -1 ])
               , function( nm )
                   data.frame( dta[1]
                             , Location = nm
                             , Measurement = dta[[nm]]
                             , stringsAsFactors = FALSE ) ) )

On June 21, 2022 9:22:48 AM PDT, Thomas Subia <thomas.subia using fmindustries.com> wrote:
>Colleagues:
>
>The header of my data set is:
>Time_stamp	P1A0B0D	P190-90D
>Jun-10 10:34	-0.000208	-0.000195
>Jun-10 10:51	-0.000228	-0.000188
>Jun-10 11:02	-0.000234	-0.000204
>Jun-10 11:17	-0.00022	-0.000205
>Jun-10 11:25	-0.000238	-0.000195
>
>I want my data set to resemble:
>
>Time_stamp	Location	Measurement
>Jun-10 10:34	P1A0B0D	-0.000208
>Jun-10 10:51	P1A0B0D	-0.000228
>Jun-10 11:02	P1A0B0D	-0.000234
>Jun-10 11:17	P1A0B0D	-0.00022
>Jun-10 11:25	P1A0B0D	-0.000238
>Jun-10 10:34	P190-90D	-0.000195
>Jun-10 10:51	P190-90D	-0.000188
>Jun-10 11:02	P190-90D	-0.000204
>Jun-10 11:17	P190-90D	-0.000205
>Jun-10 11:25	P190-90D	-0.000195
>
>I need some advice on how to do this using dplyr.
>
>V/R
>Thomas Subia
>
>FM Industries, Inc. - NGK Electronics, USA | www.fmindustries.com 
>221 Warren Ave, Fremont, CA 94539 
>
>"En Dieu nous avons confiance, tous les autres doivent apporter des donnees"
>
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-- 
Sent from my phone. Please excuse my brevity.