[R] Help with Krippendorff's Alpha
Bert Gunter
bgunter@4567 @end|ng |rom gm@||@com
Sat Jan 23 00:53:38 CET 2021
Well,....
"Appreciate the help!"
Indeed, you should for any that you receive. But do note per the posting
guide linked below:
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<http://cran.r-project.org/doc/FAQ/R-FAQ.html#Add-on-packages-in-R>), ask
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So while optimism is often a virtue, don't be disappointed if it is not
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there, so expectations of help on any of them is a long shot.
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Fri, Jan 22, 2021 at 3:24 PM Jenn Russell <jenncami using hotmail.com> wrote:
> Hello!
>
> I am requesting help for a data set in which I have 6 evaluators (I've
> called them 'Trainers'), each of which took a questionnaire with 180
> questions. The possible answers to the questions are ordinal numbers. I am
> looking to test inter-rater reliability of the questionnaire using
> Krippendorff's alpha. I have already run this in R, however when I get the
> output it seems the matrix is inverted. While it seems like it should be an
> easy problem to fix I don't see how I would be able to create my matrix the
> other way without typing out all 180 scores manually. For reference, I'm
> using the irr package to use kripp.alpha().
>
> > Trainers<-matrix(c(Trainer_1,Trainer_2, Trainer_3, Trainer_5, Trainer_6,
> Trainer_12), ncol=6)
> > kripp.alpha(Trainers, method=c("ordinal"))
> Krippendorff's alpha
> Subjects = 6
> Raters = 180
> alpha = -0.00149
>
> While I'm getting an output - shouldn't my raters be 6 and my subjects be
> 180?
>
> Appreciate the help!
>
> JR
>
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>
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