[R] rbind data frames stored in a list

[Dimitri Liakhovitski]

Thank you very much, do.call is, of course, much more elegant!
Dimitri

On Wed, Apr 22, 2009 at 9:58 PM, jim holtman <jholtman at gmail.com> wrote:
> 'do.call' is your friend::
>
>> a<-data.frame(a=1,b=2,c=3)
>> b<-data.frame(a=c(4,7),b=c(5,8),c=c(6,9))
>> c<-data.frame(a=c(10,13,16),b=c(11,14,17),c=c(12,15,18))
>> X<-list()
>> X[[1]]<-a
>> X[[2]]<-b
>> X[[3]]<-c
>> do.call(rbind, X)
>   a  b  c
> 1  1  2  3
> 2  4  5  6
> 3  7  8  9
> 4 10 11 12
> 5 13 14 15
> 6 16 17 18
>
>
> On Wed, Apr 22, 2009 at 9:36 PM, Dimitri Liakhovitski <ld7631 at gmail.com> wrote:
>> Hello everyone!
>>
>> I have a list X with 3 elements, each of which is a data frame, for example:
>>
>> a<-data.frame(a=1,b=2,c=3)
>> b<-data.frame(a=c(4,7),b=c(5,8),c=c(6,9))
>> c<-data.frame(a=c(10,13,16),b=c(11,14,17),c=c(12,15,18))
>> X<-list()
>> X[[1]]<-a
>> X[[2]]<-b
>> X[[3]]<-c
>> (X)
>>
>> How can I most effectively transform X into a data frame with columns
>> a, b, and c?
>> I would love to find a generic solution, and not a specific solution
>> like this one:
>>
>> frame<-rbind(X[[1]],X[[2]],X[[3]])
>>
>> ...because in reality I have a lot of elements of X.
>>
>> Thank you very much!
>>
>> --
>> Dimitri Liakhovitski
>> MarketTools, Inc.
>> Dimitri.Liakhovitski at markettools.com
>>
>> ______________________________________________
>> R-help at r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>
>
>
> --
> Jim Holtman
> Cincinnati, OH
> +1 513 646 9390
>
> What is the problem that you are trying to solve?
>



-- 
Dimitri Liakhovitski
MarketTools, Inc.
Dimitri.Liakhovitski at markettools.com