[R] rbind data frames stored in a list

[jim holtman]

'do.call' is your friend::

> a<-data.frame(a=1,b=2,c=3)
> b<-data.frame(a=c(4,7),b=c(5,8),c=c(6,9))
> c<-data.frame(a=c(10,13,16),b=c(11,14,17),c=c(12,15,18))
> X<-list()
> X[[1]]<-a
> X[[2]]<-b
> X[[3]]<-c
> do.call(rbind, X)
   a  b  c
1  1  2  3
2  4  5  6
3  7  8  9
4 10 11 12
5 13 14 15
6 16 17 18


On Wed, Apr 22, 2009 at 9:36 PM, Dimitri Liakhovitski <ld7631 at gmail.com> wrote:
> Hello everyone!
>
> I have a list X with 3 elements, each of which is a data frame, for example:
>
> a<-data.frame(a=1,b=2,c=3)
> b<-data.frame(a=c(4,7),b=c(5,8),c=c(6,9))
> c<-data.frame(a=c(10,13,16),b=c(11,14,17),c=c(12,15,18))
> X<-list()
> X[[1]]<-a
> X[[2]]<-b
> X[[3]]<-c
> (X)
>
> How can I most effectively transform X into a data frame with columns
> a, b, and c?
> I would love to find a generic solution, and not a specific solution
> like this one:
>
> frame<-rbind(X[[1]],X[[2]],X[[3]])
>
> ...because in reality I have a lot of elements of X.
>
> Thank you very much!
>
> --
> Dimitri Liakhovitski
> MarketTools, Inc.
> Dimitri.Liakhovitski at markettools.com
>
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> and provide commented, minimal, self-contained, reproducible code.
>



-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem that you are trying to solve?