[BioC] evaluating a character string as a variable name in an ExpressionSet object
Saroj K Mohapatra
smohapat at vbi.vt.edu
Fri Apr 17 03:28:25 CEST 2009
Hi Kavitha:
Are you looking for something like this:
> ls()
character(0)
>
# I have a string called "reallyfunnyvariable"
> mystr = "reallyfunnyvariable"
# I want to convert this to a variable with the same name; I want it to be a list
eval(parse(text=paste(mystr,"=list()",sep="")))
# Now I have the variable
> ls()
[1] "mystr" "reallyfunnyvariable"
# it is a list
> reallyfunnyvariable
list()
You have to be careful though while turning strings into variable, especially in the "batch" mode - what if the string is something like "plot"?
You might want to add a clause for first checking if the variable exists, before assigning the variable name.
Best,
Saroj
----- Original Message -----
From: "Kavitha Venkatesan" <kavitha.venkatesan at gmail.com>
To: bioconductor at stat.math.ethz.ch
Sent: Thursday, April 16, 2009 5:58:44 PM GMT -05:00 US/Canada Eastern
Subject: [BioC] evaluating a character string as a variable name in an ExpressionSet object
I would like to know how to evaluate a character string as a variable name
in R. Specifically, I need to "compute" the variable name in the phenoData
slot of an ExpressionSet object.
> varLabels(sample.ExpressionSet)
[1] "sex" "type" "score"
Now I need to retrieve the factors sample.ExpressionSet$sex,
sample.ExpressionSet$type and sample.ExpressionSet$score in turn.
Furthermore, I need to be able to generalize my code so that I can retrieve
this factor for any phenodata variable in any given ExpressionSet object.
Clearly I cannot do something like
for (i in c(1:length(varLabels(sample.ExpressionSet)))
{
class_label <- varLabels(sample.ExpresionSet)[i]
class_label_factor <- sample.ExpressionSet$class_label
}
Here class_label is interpreted as a character string by R, but I need for
it to be evaluated as a variable name. Seems straightforward, but I couldn't
figure it out...How can I do this? Thanks in advance for any help!
Kavitha
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