[R-meta] Standardized mean differences with rma.mv?
Reza Norouzian
rnorouz|@n @end|ng |rom gm@||@com
Thu Apr 18 13:04:03 CEST 2024
Will,
It seems like you're possibly extending the "measure=" argument in
rma.uni() to rma.mv() which the latter doesn't support.
Reza
On Thu, Apr 18, 2024, 5:19 AM Viechtbauer, Wolfgang (NP) via
R-sig-meta-analysis <r-sig-meta-analysis using r-project.org> wrote:
> Dear Will,
>
> I am afraid I don't understand your question. What do you mean by
> "calculation of standardized effects" and what does escalc() have to do
> with this? rma.mv() fits models, escalc() computes various types of
> effect sizes and corresponding sampling variances, so I cannot quite make
> sense of how you are contrasting these two functions.
>
> Best,
> Wolfgang
>
> > -----Original Message-----
> > From: R-sig-meta-analysis <r-sig-meta-analysis-bounces using r-project.org>
> On Behalf
> > Of Will Hopkins via R-sig-meta-analysis
> > Sent: Tuesday, April 16, 2024 23:39
> > To: 'R Special Interest Group for Meta-Analysis' <r-sig-meta-analysis using r-
> > project.org>
> > Cc: Will Hopkins <willthekiwi using gmail.com>
> > Subject: [R-meta] Standardized mean differences with rma.mv?
> >
> > I searched the archive, and if I missed it, I apologize, but is it true
> to
> > say that currently multivariate analyses of the kind offered by rma.mv
> > (when, for example, studies provide two or more estimates for the meta)
> do
> > not allow for calculation of standardized effects of the kind offered by
> > escalc (e.g., using measure="SMD1")? I realize one could do the analyses
> > oneself with rma.mv by pre-standardizing the mean effects, but you would
> > have to be quite savvy with estimating the standard errors of the
> > standardized effects.
> >
> > Will
>
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