[R-meta] Using control-only and treatment-only studies in 'metafor' -- can you calculate effect sizes with NAs in your table?
Ruecker @ending from imbi@uni-freiburg@de
Tue Oct 30 22:04:16 CET 2018
At least for me, it is still not clear how your data look like. As I understand, you have two groups of studies, treatment and control, and for each study you have an ROC. What I don't understand is (i) what the meaning of the n_i is and (ii) whether the sd_i are really standard deviations (this doesn't make sense to me) or rather standard errors (this would make sense).
If you have ROCs and their standard *errors* for each study, you may compute two verage ROCs (one for each group of studies) using a generic meta-analysis function (for example, metagen() from R package meta):
meta1 <- metagen(ROC1_i, se1_i)
meta2 <- metagen(ROC2_i, se2_i)
Note that you can compare these two averages to each other, but for the interpretation you have to bear in mind that this is an uncontrolled comparison, as you have only uncontrolled studies.
Von: Veronica Frans [verofrans using gmail.com ]
An: wolfgang.viechtbauer using maastrichtuniversity.nl Kopie: r-sig-meta-analysis using r-project.org Datum: Tue, 30 Oct 2018 15:38:20 -0400
> Hello, Wolfgang,
> Thanks for your reply.
> The 'mean accuracy score' I am referring to here is the Area Under the
> Receiver Operating Curve (a plot of true positive and false positive rates
> of a model prediction), and is calculated from testing a trained model's
> ability to accurately determine the presence of absence of an occurrence in
> a given spatial grid. Values below 0.5 indicate complete randomness, and
> values closer to 1 imply the highest predictability. It is one of the
> standard measures of species distribution modeling in ecology, and I am
> using this score to test models that follow a newer procedure (the
> treatment) versus models that don't (the control). The goal is to see if
> the treatment has a greater effect on accuracy than the control.
> I am obviously new to meta-analyses, so any suggestions are definitely
> appreciated. Thanks again for your help!
> On Tue, Oct 30, 2018 at 2:40 PM Viechtbauer, Wolfgang (SP) <
> wolfgang.viechtbauer using maastrichtuniversity.nl wrote:
>> Dear Veronica,
>> Measure 'SMD' is for computing the standardized mean difference between
>> two groups. It does not seem applicable to your data.
>> Can you describe in a bit more detail what these "mean accuracy scores"
>> are? How are they computed within an individual study?
>> -----Original Message-----
>> From: R-sig-meta-analysis [mailto:
>> r-sig-meta-analysis-bounces using r-project.org ] On Behalf Of Veronica Frans
>> Sent: Tuesday, 30 October, 2018 18:29
>> To: r-sig-meta-analysis using r-project.org Subject: [R-meta] Using control-only and treatment-only studies in
>> 'metafor' -- can you calculate effect sizes with NAs in your table?
>> Dear forum,
>> I would like to use the 'metafor' package for my meta-analysis. I am
>> comparing the results (mean accuracy score from 0 to 1) of articles that
>> use one procedure (the 'treatment'; group 1) versus those that don't (the
>> 'control'; group 2). However, all of my studies present results for only
>> the treatment or only the control, but never both.
>> To run the escalc() function (measure=SMD), is it possible to have studies
>> with NA's in m1i, sd1i, n1i, and vice-versa?
>> Unfortunately, when I use my table in R, the escalc() function gives me
>> NA's for yi and vi.
>> Here's an example of the code I used:
>> mod.means <-data.frame(
>> study = c("UID6","UID7","UID11","UID13","UID17","UID18"),
>> n1i = c(1,1,16,NA,NA,21), #number in treatment
>> n2i = c(NA,NA,NA,2,2,NA), #number in control
>> m1i = c(.931,.81,.977,NA,NA,.878), #treatment means
>> m2i = c(NA,NA,NA,.865,.69,NA), #control means
>> sd1i = c(0,0,.012,NA,NA,.0386), #treatment sd
>> sd2i = c(NA,NA,NA,.05,.03,NA), #control sd
>> scale = c(3,4,1,1,3,2) #potential moderator
>> all.meta <- escalc(measure = "SMD",
>> m1i = m1i, m2i=m2i, #means
>> sd1i=sd1i, sd2i = sd2i, #standard deviation
>> n1i=n1i, n2i = n2i, #numbers
>> data = mod.means)
>> all.meta #show table
>> Perhaps I should format my table in a different way or consider a different
>> meta-analysis approach other than "SMD"?
>> Any advice on this is greatly appreciated. Thank you for your time!
>> Veronica Frans
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