[R-sig-Geo] dclf.test output.
Guy Bayegnak
Guy.Bayegnak at gov.ab.ca
Thu Jul 28 00:59:23 CEST 2016
Thanks for your response Rolf,
You summarized it correctly. However, B and D do not necessarily avoid each other. They could and do in fact occur next to each other at times just by coincidence, simply because both categories tend to occur all over the place, while I think A and C are influenced by D. I included the alternative="greater" but I still get the same results.
A sample of my data is provided below( I have more than 800 points).
Longitude Latitude Type
1 -113.1923 51.02913 C
2 -113.2013 52.83306 A
3 -113.6834 51.06585 A
4 -113.0295 50.97140 C
5 -113.2366 50.96440 A
6 -113.5849 51.37568 A
7 -113.6877 51.09027 D
8 -113.5371 51.82780 D
I used the following code and got the results provided earlier:
dclf.test(Data.ppp,Kcross, i = "A", j = "D", alternative="greater" ,correction = "border")
dclf.test(Data.ppp,Kcross, i = "B", j = "D", alternative="greater" ,correction = "border")
dclf.test(Data.ppp,Kcross, i = "C", j = "D", alternative="greater" ,correction = "border")
Thanks,
GAB
-----Original Message-----
From: Rolf Turner [mailto:r.turner at auckland.ac.nz]
Sent: Wednesday, July 27, 2016 3:48 PM
To: Guy Bayegnak
Cc: r-sig-geo at r-project.org
Subject: Re: [R-sig-Geo] dclf.test output.
I gather that your problem is that you expect to reject the null hypothesis of "no clustering" for A vs. D and for C vs. D, but *not* to reject it for B vs. D.
I *think* that your problem might be the fact that you are using a two-sided test, which gives, roughly speaking, a test of "no association" rather than a test of "no clustering". It could be the case that points of types B and D tend to *avoid* each other, so you get "significant" association between B and D, although the B points do the opposite of clustering around D points.
It's hard to tell for sure without a *reproducible example* (!!!). We don't have access to Data.ppp.
Try using alternative="greater" in your call to dclf.test() and see if the results are more in keeping with your expectations.
cheers,
Rolf Turner
--
Technical Editor ANZJS
Department of Statistics
University of Auckland
Phone: +64-9-373-7599 ext. 88276
On 28/07/16 05:48, Guy Bayegnak wrote:
> Hi all, I have some marked spatial points and I am trying to assess
> therelative association between different types of points using the
> Diggle-Cressie-Loosmore-Ford test of CSR.
> My observations are of 4 categories (A,B,C,D) and I am trying to
> assess 3 categories (A,B,C,) against one (D), and I get the output
> provided below. Knowing the sampling area, I know category "D" and
> category "B" tend to occur all across the sampling area.
> What I am trying to prove is that category "A" and "C" tend to be
> clustered around "D". But u values I am getting are all positive, and
> the p-value are all 0.01. However, the dclf.test between A-D and C-D
> returns a u value at least 3 times as large than that of B-D.
> My question is: how do I interpret these values. Does it still show
> clustering of A and C relative to D? if yes how do I interpret the
> output of dclf.test between B and D?
> Thanks, GAB
>
>
>
> Diggle-Cressie-Loosmore-Ford test of CSR
> Monte Carlo test based on 99 simulations
> Summary function: Kcross["A", "D"](r)
> Reference function: theoretical
> Alternative: two.sided
> Interval of distance values: [0, 1.05769125]
> Test statistic: Integral of squared absolute deviation
> Deviation = observed minus theoretical
>
> data: Data.ppp
> u = 54.931, rank = 1, p-value = 0.01
>
> Diggle-Cressie-Loosmore-Ford test of CSR
> Monte Carlo test based on 99 simulations
> Summary function: Kcross["B", "D"](r)
> Reference function: theoretical
> Alternative: two.sided
> Interval of distance values: [0, 1.05769125]
> Test statistic: Integral of squared absolute deviation
> Deviation = observed minus theoretical
>
> data: Data.ppp
> u = 19.315, rank = 1, p-value = 0.01
>
> Diggle-Cressie-Loosmore-Ford test of CSR
> Monte Carlo test based on 99 simulations
> Summary function: Kcross["C", "D"](r)
> Reference function: theoretical
> Alternative: two.sided
> Interval of distance values: [0, 1.05769125]
> Test statistic: Integral of squared absolute deviation
> Deviation = observed minus theoretical
>
> data: Data.ppp
> u = 46.829, rank = 1, p-value = 0.01
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