[R] how can I convert a long to wide matrix?
Jim Lemon
drj|m|emon @end|ng |rom gm@||@com
Wed May 2 01:05:05 CEST 2018
Hi Marna,
I think this is due to having three rows for id_X and only two for
id_Y. The function creates a data frame with enough columns to hold
the greatest number of values for each ID variable. Notice that the
SITE_n columns contain three values for id_X (A, A, B) and two for
id_Y (A, B, NA) as there was no third occasion of measurement for the
latter. Even though there are only two _values_ for SITE, there must
be enough space for three. In your desired output, SITE for the second
occasion of measurement is wrong (it should be "A"), and for the third
occasion it is unknown. Even if there was only one value for SITE in
the original data frame, it should be repeated for the correct number
of observations. I think you may be mixing up case ID with location of
observation.
Jim
On Wed, May 2, 2018 at 8:48 AM, Marna Wagley <marna.wagley using gmail.com> wrote:
> Hi Jim,
> Thank you very much for your suggestions. I used it but it gave me three
> sites. But actually I do have only two sites "Id_X" and "Id_y" . In fact
> "A" is repeated two times for "Id_X". If it is repeated, I would like to
> take the first one among many repeated values.
>
> dat<-structure(list(ID = structure(c(1L, 1L, 1L, 2L, 2L), .Label = c("id_X",
>
> "id_Y"), class = "factor"), EventDate = structure(c(4L, 5L, 2L,
>
> 3L, 1L), .Label = c("9/15/16", "9/15/17", "9/7/16", "9/8/16",
>
> "9/9/16"), class = "factor"), timeGroup = structure(c(1L, 1L,
>
> 2L, 1L, 2L), .Label = c("B1", "B2"), class = "factor"), SITE =
> structure(c(1L,
>
> 1L, 2L, 1L, 2L), .Label = c("A", "B"), class = "factor")), .Names = c("ID",
>
> "EventDate", "timeGroup", "SITE"), class = "data.frame", row.names = c(NA,
>
> -5L))
>
> library(prettyR)
>
> stretch_df(dat,idvar="ID",to.stretch=c("EventDate","SITE"))
>
>
> ID timeGroup EventDate_1 EventDate_2 EventDate_3 SITE_1 SITE_2 SITE_3
> 1 id_X B1 9/8/16 9/9/16 9/15/17 A A B
> 2 id_Y B1 9/7/16 9/15/16 <NA> A B <NA>
>>
>
> Basically I am looking for like following table
>
> ID timeGroup EventDate_1 EventDate_2 EventDate_3 SITE_1 SITE_2
> 1 id_X B1 9/8/16 9/9/16 9/15/17 A B
> 2 id_Y B1 9/7/16 9/15/16 <NA> A B
>
> Thanks
>
>
> On Tue, May 1, 2018 at 3:32 PM, Jim Lemon <drjimlemon using gmail.com> wrote:
>>
>> Hi Marna,
>> Try this:
>>
>> library(prettyR)
>> stretch_df(dat,idvar="ID",to.stretch=c("EventDate","SITE"))
>>
>> Jim
>>
>>
>> On Wed, May 2, 2018 at 8:24 AM, Marna Wagley <marna.wagley using gmail.com>
>> wrote:
>> > Hi R user,
>> > I was trying to convert a long matrix to wide? I have an example and
>> > would
>> > like to get a table (FinalData1):
>> >
>> >
>> > FinalData1
>> > B1 B2
>> > id_X "A" "B"
>> > id_Y "A" "B"
>> >
>> > but I got the following table using the following code.
>> >
>> > FinalData1
>> >
>> > B1 B2
>> >
>> > id_X "A" "A"
>> >
>> > id_Y "A" "B"
>> >
>> >
>> > the code and the example data I used are given below. Is there any
>> > suggestions to fix the problem?
>> >
>> >
>> > dat<-structure(list(ID = structure(c(1L, 1L, 1L, 2L, 2L), .Label =
>> > c("id_X",
>> >
>> >
>> > "id_Y"), class = "factor"), EventDate = structure(c(4L, 5L, 2L,
>> >
>> > 3L, 1L), .Label = c("9/15/16", "9/15/17", "9/7/16", "9/8/16",
>> >
>> > "9/9/16"), class = "factor"), timeGroup = structure(c(1L, 1L,
>> >
>> > 2L, 1L, 2L), .Label = c("B1", "B2"), class = "factor"), SITE =
>> > structure(c(
>> > 1L,
>> >
>> > 1L, 2L, 1L, 2L), .Label = c("A", "B"), class = "factor")), .Names =
>> > c("ID",
>> >
>> > "EventDate", "timeGroup", "SITE"), class = "data.frame", row.names =
>> > c(NA,
>> >
>> > -5L))
>> >
>> >
>> > tmp <- split(dat, dat$ID)
>> >
>> > tmp1 <- do.call(rbind, lapply(tmp, function(dat){
>> >
>> > tb <- table(dat$timeGroup)
>> >
>> > idx <- which(tb>0)
>> >
>> > tb1 <- replace(tb, idx, as.character(dat$SITE))
>> >
>> > }))
>> >
>> >
>> > tmp1
>> >
>> > FinalData<-print(tmp1, quote=FALSE)
>> >
>> > [[alternative HTML version deleted]]
>> >
>> > ______________________________________________
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>
>
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