[R] how can I convert a long to wide matrix?

[Marna Wagley]

Hi Jim,
Thank you very much for your suggestions. I used it but it gave me three
sites. But actually I do have only two sites "Id_X" and "Id_y" . In fact
"A" is repeated two times for "Id_X". If it is repeated, I would like to
take the first one among many repeated values.

dat<-structure(list(ID = structure(c(1L, 1L, 1L, 2L, 2L), .Label = c("id_X",


"id_Y"), class = "factor"), EventDate = structure(c(4L, 5L, 2L,

3L, 1L), .Label = c("9/15/16", "9/15/17", "9/7/16", "9/8/16",

"9/9/16"), class = "factor"), timeGroup = structure(c(1L, 1L,

2L, 1L, 2L), .Label = c("B1", "B2"), class = "factor"), SITE = structure(c(
1L,

1L, 2L, 1L, 2L), .Label = c("A", "B"), class = "factor")), .Names = c("ID",

"EventDate", "timeGroup", "SITE"), class = "data.frame", row.names = c(NA,

-5L))

library(prettyR)

stretch_df(dat,idvar="ID",to.stretch=c("EventDate","SITE"))

ID timeGroup EventDate_1 EventDate_2 EventDate_3 SITE_1 SITE_2 SITE_3
1 id_X        B1      9/8/16      9/9/16     9/15/17      A      A      B
2 id_Y        B1      9/7/16     9/15/16        <NA>      A      B   <NA>
>

Basically I am looking for like following table

ID timeGroup EventDate_1 EventDate_2 EventDate_3 SITE_1 SITE_2
1 id_X        B1      9/8/16      9/9/16     9/15/17      A      B
2 id_Y        B1      9/7/16     9/15/16        <NA>      A      B

Thanks


On Tue, May 1, 2018 at 3:32 PM, Jim Lemon <drjimlemon using gmail.com> wrote:

> Hi Marna,
> Try this:
>
> library(prettyR)
> stretch_df(dat,idvar="ID",to.stretch=c("EventDate","SITE"))
>
> Jim
>
>
> On Wed, May 2, 2018 at 8:24 AM, Marna Wagley <marna.wagley using gmail.com>
> wrote:
> > Hi R user,
> > I was trying to convert a long matrix to wide? I have an example and
> would
> > like to get a table (FinalData1):
> >
> >
> > FinalData1
> >          B1    B2
> > id_X   "A"   "B"
> > id_Y   "A"   "B"
> >
> > but I got the following table using the following code.
> >
> > FinalData1
> >
> >      B1  B2
> >
> > id_X "A" "A"
> >
> > id_Y "A" "B"
> >
> >
> > the code and the example data I used are given below. Is there any
> > suggestions to fix the problem?
> >
> >
> > dat<-structure(list(ID = structure(c(1L, 1L, 1L, 2L, 2L), .Label =
> c("id_X",
> >
> >
> > "id_Y"), class = "factor"), EventDate = structure(c(4L, 5L, 2L,
> >
> > 3L, 1L), .Label = c("9/15/16", "9/15/17", "9/7/16", "9/8/16",
> >
> > "9/9/16"), class = "factor"), timeGroup = structure(c(1L, 1L,
> >
> > 2L, 1L, 2L), .Label = c("B1", "B2"), class = "factor"), SITE =
> structure(c(
> > 1L,
> >
> > 1L, 2L, 1L, 2L), .Label = c("A", "B"), class = "factor")), .Names =
> c("ID",
> >
> > "EventDate", "timeGroup", "SITE"), class = "data.frame", row.names =
> c(NA,
> >
> > -5L))
> >
> >
> > tmp <- split(dat, dat$ID)
> >
> > tmp1 <- do.call(rbind, lapply(tmp, function(dat){
> >
> > tb <- table(dat$timeGroup)
> >
> > idx <- which(tb>0)
> >
> > tb1 <- replace(tb, idx, as.character(dat$SITE))
> >
> > }))
> >
> >
> > tmp1
> >
> > FinalData<-print(tmp1, quote=FALSE)
> >
> >         [[alternative HTML version deleted]]
> >
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