[R] need for help for solving operations in a vector

[PIKAL Petr]

Hi

On top of answers you have got here is some plotting you need to answer yourself

plot(qWC1, col=(c(0, diff(qWC1))>=0 )+1)

Which from those red points you want to be included in irrigation period? All of them? Only part? Which part?

Based on your figures you probably will not get 100% correct answer.

Cheers
Petr



> -----Original Message-----
> From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Makram
> Belhaj Fraj
> Sent: Wednesday, December 23, 2015 8:35 AM
> To: r-help at r-project.org; r-help-owner at r-project.org
> Subject: [R] need for help for solving operations in a vector
>
>  Dear colleagues
> i need your generous help to solve the following problem
>
> I have a  soil moisture time series qWC1 (61 values)
> > qWC1
>  75.33336 75.20617 75.20617 74.95275 74.95275 74.70059 74.70059
> 74.70059
> 74.57498 74.44968 74.32469 74.07563  85.57237 90.40123 90.73760
> 90.73760 90.73760 90.73760 90.90648 91.07582 91.24564 90.90648 86.82135
> 80.69793
> 79.30393 78.62058 78.21484 77.81226 77.67876 77.41279 77.28032 76.88495
> 76.75383 76.75383 76.49260 76.36249  76.23270 76.23270 76.10325
> 75.97412
> 75.84532 75.71685  75.71685 75.71685 75.71685 75.46087 75.46087
> 75.46087
> 75.33336 75.20617 75.20617 75.20617 75.20617 75.20617 75.20617 75.07930
> 75.07930 75.07930 74.95275 74.95275  74.95275
>
> I want to measure consecutive increases corresponding to irrigation and
> consecutive decreases  corresponding to recharge I wrote the following
> code and it does not calculate for each increment in i?
> also note that I choose to not use diff command in time series because
> I  want also that "plateaux" corresponding to a minimum of 2 equal
> consecutive values are accounted as positive differences=irrigations so
> when x[i+1]==x[i] the difference y might be equal to the previous value
> xi
>
> following the code i wrote
>
> x<-ts(qWC1,start=1, end=61, frequency=1) x[1] plot(x, type="h", col =
> "green")
> y<-rep(0,61)
> for (i in 1:61) {
> if (x[i+1] > x[i]){
>     y[i]==x[i+1]-x[i]
> } else if (x[i+1]==x[i]){
>     y[i]=x[i+2]-x[i]
> } else {
>     y[i]==x[i+1]-x[i]
> }
>
> }
> plot(y, type="h", col = "blueviolet")
>
> Many thank
> Makram
>
>       [[alternative HTML version deleted]]
>
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> guide.html
> and provide commented, minimal, self-contained, reproducible code.

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