[R] attribute and main value
Gerrit Draisma
gdraisma at xs4all.nl
Mon Dec 29 17:57:40 CET 2014
Thanks Bill,
That is what I was looking for.
Gerrit
On 12/29/2014 05:53 PM, William Dunlap wrote:
> as.vector(x) will return x without any attributes and
> structure(x, attrA=NULL, attrB=NULL) will return x
> without the named attributes.
> > z <- f(1:3, 4)
> > z
> [1] 14
> attr(,"gradient")
> [1] -6 -4 -2
> > as.vector(z)
> [1] 14
> > structure(z, gradient=NULL)
> [1] 14
>
> as.vector is a generic function, so for certain classes
> (e.g., factor) it may do more than just strip attributes.
> Matrix dimensions are attributes and will be removed by
> as.vector.
>
>
>
> Bill Dunlap
> TIBCO Software
> wdunlap tibco.com <http://tibco.com>
>
> On Mon, Dec 29, 2014 at 8:17 AM, Gerrit Draisma <gdraisma at xs4all.nl
> <mailto:gdraisma at xs4all.nl>> wrote:
>
> Thanks Duncan.
>
> But my question was how to extract
> simply the function value from value,
> without the gradient attribute?
>
> I see that things like value<2 give the right answer.
> I was curiosity. I found now that value[1]
> gives strips the attributes from value:
> ------
> > value
> [1] 1
> attr(,"gradient")
> [1] 2
> > value[1]
> [1] 1
> ------
> Is that the way?
>
> Gerrit
>
>
>
> On 12/29/2014 05:05 PM, Duncan Murdoch wrote:
>
> On 29/12/2014 10:32 AM, Gerrit Draisma wrote:
>
> Just a curiosity question:
>
> In the documentation for the nlm procedure
> a find this example of defining a function
> with a gradient attribute:
> -----------
> f <- function(x, a)
> {
> res <- sum((x-a)^2)
> attr(res, "gradient") <- 2*(x-a)
> res
> }
> -----------
> I get the gradient with
> attr(f(3,2),"gradient")
> but how do I get the function value it self?
>
>
> value <- f(3,2)
> gradient <- attr(value, "gradient")
>
> Duncan Murdoch
>
>
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