[R] how to add a row vector in a dataframe
arun
smartpink111 at yahoo.com
Tue Apr 16 05:12:21 CEST 2013
Hi,
May be this helps you.
#Using
set.seed(12345)
S=10
simdata <- replicate(S, generate(250))
lstpshat<-lapply(seq_len(ncol(simdata)),function(i) {glm.t<-glm(t~x1+x2+x3+x4+x5+x6+x7+I(x2^2)+I(x4^2)+I(x7^2)+x1:x3+x2:x4+x3:x5+x4:x6+x5:x7+x1:x6+x2:x3+x3:x4+x4:x5+x5:x6,family=binomial,data=simdata[,i]); pshat<- predict(glm.t,type="response")})
simdata1<-rbind(simdata,pshat=lstpshat)
pdf("hist1.pdf")
lapply(seq_len(ncol(simdata1)),function(i){ x1<- simdata1[,i]; pshat0<-x1$pshat[x1$t==0];pshat1<- x1$pshat[x1$t==1]; hist(pshat1,xlim=c(0,1),col=rgb(0.7,0,0,0.5)); hist(pshat0,add=T,col=rgb(0,0,1,0.3))})
dev.off()
(You need to change the colors as per your requirements)
A.K.
>thanks! it really helps!
>
>anyway, how will i have a histogram of the lstpshat basing on
the value of t, that is, fot t=1, the color is red, for t=0, the color
is blue and for their >overlap, the color is green? thanks a lot!
>
>set.seed(12345)
>S=1000
>generate <- function(size) {
>x1 <- rnorm(size, mean=0, sd=1)
>x2 <- rnorm(size, mean=0, sd=1)
>x3 <- rnorm(size, mean=0, sd=1)
>x4 <- rnorm(size, mean=0, sd=1)
>x5 <- rnorm(size, mean=0, sd=1)
>x6 <- rnorm(size, mean=0, sd=1)
>x7 <- rnorm(size, mean=0, sd=1)
>x8 <- rnorm(size, mean=0, sd=1)
>x9 <- rnorm(size, mean=0, sd=1)
>x10 <- rnorm(size, mean=0, sd=1)
>e<-rnorm(size, mean=0, sd=1)
>t_trueps <- (1 + exp( -(b0 + b1*x1 + b2*x2 + b3*x3 + b4*x4 + b5*x5 + b6*x6 + b7*x7
>+ b2*x2*x2 + b4*x4*x4 + b7*x7*x7 + b1*0.5*x1*x3 + b2*0.7*x2*x4 +b3*0.5*x3*x5
>+ b4*0.7*x4*x6 + b5*0.5*x5*x7 + b1*0.5*x1*x6 + b2*0.7*x2*x3 + b3*0.5*x3*x4
>+ b4*0.5*x4*x5 + b5*0.5*x5*x6) ) )^-1
>prob.exposure <- runif(size)
>t <- ifelse(t_trueps > prob.exposure, 1, 0)
>y <- a0 + a1*x1 + a2*x2 + a3*x3 + a4*x4 +a5*x8 + a6*x9 + a7*x10 + g1*t + e
>sim <- as.data.frame(cbind(x1, x2, x3 ,x4, x5, x6, x7, x8, x9, x10, t, y))
>return(sim)
>}
>b0 <- 0.05
>b1 <- 0.95
>b2 <- -0.25
>b3 <- 0.6
>b4 <- -0.4
>b5 <- -0.8
>b6 <- -0.5
>b7 <- 0.7
>a0 <- -3.85
>a1 <- 0.3
>a2 <- -0.36
>a3 <- -0.73
>a4 <- -0.2
>a5 <- 0.71
>a6 <- -0.19
>a7 <- 0.26
>g1 <- -0.4
>simdata <- replicate(S, generate(3000))
>
>lstpshat<-lapply(seq_len(ncol(simdata)),function(i)
>{glm.t<-glm(t~x1+x2+x3+x4+x5+x6+x7+I(x2^2)+I(x4^2)+I(x7^2)+x1:x3+x2:x4+x3:x5+x4:x6+x5:x7+x1:x6+x2:x3+x3:x4+x4:x5+x5:x6,family=binomial,data=simdata[,i]);
>
>pshat<- predict(glm.t,type="response")})
>simdata1<-rbind(simdata,pshat=lstpshat)
>
>simdata.ps1<- simdata1
>simdata.ps1[]<-do.call(c,lapply(seq_len(ncol(simdata1)),function(i)
lapply(simdata1[,i],function(x) x[simdata1[,i]$t==1])))
>lstm1<- lapply(seq_len(ncol(simdata.ps1)),function(i)
{dat<-do.call(data.frame,lapply(simdata.ps1[,i],function(x)
x));if(nrow(dat)!=0) >{glm.1<-glm(y~x1+x2+x3+x4+x8+x9+x10,data=dat)}
else NULL; glm.1; m1<- predict(glm.1)})
>
>simdata.ps0<- simdata1
>simdata.ps0[]<-do.call(c,lapply(seq_len(ncol(simdata1)),function(i)
lapply(simdata1[,i],function(x) x[simdata1[,i]$t==0])))
>lstm0<-lapply(seq_len(ncol(simdata.ps0)),function(i)
{dat<-do.call(data.frame,lapply(simdata.ps0[,i],function(x)
x));if(nrow(dat)!=0) >{glm.0<-glm(y~x1+x2+x3+x4+x8+x9+x10,data=dat)}
else NULL; glm.0; m0<- predict(glm.0)})
>
>simdata.psm1<- rbind(simdata.ps1,m1=lstm1)
>simdata.psm0<- rbind(simdata.ps0,m0=lstm0)
>
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