[R] For loop with i and j and multiple if statements... help!

[ingaschwabe]

Dear all!

I'm quite new to R and at this moment a little bit lost in trying to make a
function work with a for loop 
that has two variables (i and j) and multiple if statements.. 
I hope that someone of you could help me. I would very appreciate it!

What do I want to do? I am analysing the data of an 'eye tracker'. The eye
tracker registers the coordinates to which participants looked while reading
a website. 

The data looks like this: 

 Number   x   y
1      1 701 209
2      2 685 209
3      3 566 248
4      4 562 234
5      5 601 225
6      6 608 232
[....]

To assign look zones, I looked which zone (e.g. the references) is
represented by which coordinates. This give the following results: 
Look zone 1 = x > 170, x < 1250, y > 150 and y < 480
look sone 2 = x > 170, x < 420, y > 480 and y < 810. 

Now I would like to assign a lookzone for each subject by the means of a
function with a for loop. 

I've made this: 

lookzones <- function(input){

                lookzone <- matrix(0, nrow(input), 1)#Make space for
lookzone variables
                                                                           
for(i in 1:nrow(input)){
for(j in 1:nrow(input)){
                 if (x[i] > 170 && x[i] < 1250 && x[j] > 150 && y[j] < 480)
{lookzone <- 1}
                 if (x[i] > 170 && x[i] < 420  && x[j] > 480 && y[j] < 810)
{lookzone <- 2}
                          }
            list(lookzone = lookzone)
                    input <- cbind(input, lookzone)
                        }
} 

First, there is a variable made (lookzone) in which the values of the
lookzones can be stored. Then in the for loop, it is tested whether all
conditions are met (see above) and then a value is assigned to the lookzone
variable. 
The input variable is a data set that looks like the data above. 

However, the function does not seem to work. 
When I run it, R assigns a value '1' to every x/y combination. 

Can someone help me with this? 

Thank you so much ! 

Bye, inga



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