[R] using 'apply' to apply princomp to an array of datasets

[Rui Barradas]

Hello,

As for the first question try

scoreset <- lapply(pcl, function(x) x$scores[, 1])
do.call(cbind, scoreset)


As for the second question, you want to know which columns in 'datasets' 
have NA's?

colidx <- apply(datasets, 2, function(x) any(is.na(x)))
datasets[, colidx]  # These have NA's


For the column numbers you can do

colnums <- which(colidx)

Hope this helps,

Rui Barradas

Em 12-12-2012 17:14, David Romano escreveu:
> Hi everyone,
>
> Suppose I have a 3D array of datasets, where say dimension 1 corresponds to
> cases, dimension 2 to datasets, and dimension 3 to observations within a
> dataset.  As an example, suppose I do the following:
>
>> x <- sample(1:20, 48, replace=TRUE)
>> datasets <- array(x, dim=c(4,3,2))
> Here, for each j=1,2,3, I'd like to think of datasets[,j,] as a single data
> matrix with four cases and two observations.  Now, I'd like to be able to
> do the following: apply pca to each dataset, and create a matrix of the
> first principal component scores.
>
> In this example, I could do:
>
>> pcl<-apply(datasets,2,princomp)
> which yields a list of princomp output, one for each dataset, so that the
> vector of first principal component scores for dataset 1 is obtained by
>
>> score1set1 <- pcl[[1]]$scores[,1]
> and I could then obtain the desired matrix by
>
>> score1matrix <- cbind( score1set1, score1set2, score1set3)
>
> So my first question is: 1) how could I use *apply to do this?  I'm having
> trouble because pcl is a list of lists, so I can't use, say, do.call(cbind,
> ...) without first having a list of the first component score vectors,
> which I'm not sure how to produce.
>
> My second question is: 2) Having answered question 1), now suppose there
> may be datasets containing NA value -- how could I select the subset of
> values from dimension 2 corresponding to the datasets for which this is
> true (again using *apply?)?
>
> Thanks in advance for any light you might be able to shed on these
> questions!
>
> David Romano
>
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>
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