[R] Sampling with conditions
(Ted Harding)
ted.harding at wlandres.net
Tue Nov 8 08:41:05 CET 2011
[Correction below (I was writing too late at night ... ]
On 08-Nov-11 00:25:57, Ted Harding wrote:
> On 07-Nov-11 22:22:54, SarahJoyes wrote:
>> Hey everyone,
>> I am at best, an amateur user of R, but I am stuck on how
>> to set-up the following situation.
>> I am trying to select a random sample of numbers from 0 to 10
>> and insert them into the first column of a matrix (which will
>> used later in a loop).
>> However, I need to have those numbers add up to 10. How can
>> I set those conditions?
>> So far I have:
>> n<-matrix(0,nr=5,ncol=10)
>> for(i in 1:10){n[i,1]<-sample(0:10,1)}
>> How do I set-up the "BUT sum(n[i,1])=10"?
>> Thanks
>> SarahJ
>
> Sarah, your example is confusing because you have set up a
> matrix 'n' with 5 rows and 10 columns. But your loop cycles
> through 10 rows!
>
> However, assuming that your basic requirement is to sample
> 10 integers which add up to 10, consider rmultinom():
>
> rmultinom(n=1,size=10,prob=(1:10)/10)
> # [,1]
> # [1,] 1
> # [2,] 0
> # [3,] 2
> # [4,] 0
> # [5,] 1
> # [6,] 1
> # [7,] 2
> # [8,] 0
> # [9,] 1
> #[10,] 2
> rmultinom(n=1,size=10,prob=(1:10)/10)
> # [,1]
> # [1,] 0
> # [2,] 0
> # [3,] 0
> # [4,] 0
> # [5,] 1
> # [6,] 1
> # [7,] 2
> # [8,] 1
> # [9,] 2
> #[10,] 3
>
> This gives each integer in (0:10) equal chances of being
> in the sample. For unequal chances, vary 'prob'.
>
> Hoping this helps,
> Ted.
That should have read:
This gives a uniform distribution over the positions in
the sample vector for the sampled integers, so that all
permutations are equally likely. For a non-uniform
distribution, vary 'prob'.
Sorry,
Ted.
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Date: 08-Nov-11 Time: 07:40:51
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