[R] How to assign week numbers to a time-series
David Winsemius
dwinsemius at comcast.net
Sat Mar 6 00:26:06 CET 2010
On Mar 5, 2010, at 4:46 PM, David Winsemius wrote:
>
> On Mar 5, 2010, at 4:23 PM, Hosack, Michael wrote:
>
>> Hello everyone,
>>
>> My progress has stalled on finding a way of creating a somewhat
>> complicated variable to add to my existing dataframe and I am
>> hoping one of you could help me out. The dataframe below contains
>> only a fraction of the data of my complete dataframe, but all of
>> the variables. What I want to do is add another variable named
>> 'WEEK' to this dataframe that is assigned 1 for row 1 and remains 1
>> until the first SAT (i.e. Saturday) under variable 'DOW' (day of
>> week) occurs, at which point variable 'WEEK' is now assigned 2.
>> 'WEEK' should continue to be assigned 2 until the following SAT
>> under variable 'DOW' at which variable 'WEEK' will now be assigned
>> 3, and so on. In this scheme, weekdays are such that SAT=1, SUN=2,
>> MON=3,.....FRI=7. I am basically trying to assign week numbers to
>> potential sampling days in a survey season for use in a program
>> that will generate a fisheries creel survey schedule. I should note
>> that if element 1 happens to have DOW=SAT (that is the case this
>> year, since!
>> the first day of our survey 05/01 is a Saturday), then WEEK 1
>> begins on day 1 (05/01/2010) and WEEK 2 will begin on the first SAT
>> under variable DOW. I hope I explained this clearly enough, if not
>> let me know. If this sent twice, I apologize.
>>
>> Mike
>>
>> MM DD YR DOW DOW. DTYPE TOD TOD. SITENUM DESC
>> 1 05 01 2010 SAT 1 2 MORN 1
>> 101 WALNUT.CK
>> 185 05 01 2010 SAT 1 2 MORN 1
>> 102 LAMPE
>> 369 05 01 2010 SAT 1 2 MORN 1
>> 103 EAST.AVE
>> 553 05 01 2010 SAT 1 2 MORN 1
>> 104 NORTH.EAST
>> 737 05 01 2010 SAT 1 2 AFTN 2
>> 101 WALNUT.CK
>> 921 05 01 2010 SAT 1 2 AFTN 2
>> 102 LAMPE
>> 1105 05 01 2010 SAT 1 2 AFTN 2
>> 103 EAST.AVE
>> 1289 05 01 2010 SAT 1 2 AFTN 2
>> 104 NORTH.EAST
>> 2 05 02 2010 SUN 2 2 MORN 1
>> 101 WALNUT.CK
>> 186 05 02 2010 SUN 2 2 MORN 1
>> 102 LAMPE
>> 370 05 02 2010 SUN 2 2 MORN 1
>> 103 EAST.AVE
>> 554 05 02 2010 SUN 2 2 MORN 1
>> 104 NORTH.EAST
>> 738 05 02 2010 SUN 2 2 AFTN 2
>> 101 WALNUT.CK
>> 922 05 02 2010 SUN 2 2 AFTN 2
>> 102 LAMPE
>> 1106 05 02 2010 SUN 2 2 AFTN 2
>> 103 EAST.AVE
>> 1290 05 02 2010 SUN 2 2 AFTN 2
>> 104 NORTH.EAST
>> 3 05 03 2010 MON 3 1 MORN 1
>> 101 WALNUT.CK
>> 187 05 03 2010 MON 3 1 MORN 1
>> 102 LAMPE
>> 371 05 03 2010 MON 3 1 MORN 1
>> 103 EAST.AVE
>> 555 05 03 2010 MON 3 1 MORN 1
>> 104 NORTH.EAST
>> 739 05 03 2010 MON 3 1 AFTN 2
>> 101 WALNUT.CK
>> 923 05 03 2010 MON 3 1 AFTN 2
>> 102 LAMPE
>> 1107 05 03 2010 MON 3 1 AFTN 2
>> 103 EAST.AVE
>> 1291 05 03 2010 MON 3 1 AFTN 2
>> 104 NORTH.EAST
>> 4 05 04 2010 TUE 4 1 MORN 1
>> 101 WALNUT.CK
>> 188 05 04 2010 TUE 4 1 MORN 1
>> 102 LAMPE
>> 372 05 04 2010 TUE 4 1 MORN 1
>> 103 EAST.AVE
>> . . . . . . . . . . .
>
> You could trunc() the results of this function applied to your dates
> and "2010-05-01":
>
> > diffweek <- function(x,y) {difft <- difftime( x , y)/7;
> attr(difft, "units") <- "weeks"; difft}
> > diffweek(Sys.Date() , as.Date("2010-01-01") )
> Time difference of 9 weeks
> > diffweek(Sys.Date()+1 , as.Date("2010-01-01") )
> Time difference of 9.142857 weeks
>
> There is also a week function in the tis package.
>
> Perhaps (untested):
>
> dfrm$weeknum <- trunc(apply(dfrm, 1, function(x)
> diffweek(as.Date(x[4], x[2], x[3], sep="-") ,
>
> as.Date("2010-05-01")
> )
> ) )
>
Well, testing shows that it fails. I didn't get an apply() based
solution to work and needed to vectorize diffweek:
diffweekV <- Vectorize(diffweek)
seqwk <- with(dfrm , as.Date(paste(YR, MM, DD, sep="-")) )
dfrm$weeknum <- 1+ trunc(diffweekV(seqwk, as.Date("2010-05-01") ) )
(Which looks clearer anyway.)
I did throw a few other values at the function to see if it had
sensible return values.
> --
>
> David Winsemius, MD
> West Hartford, CT
>
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David Winsemius, MD
West Hartford, CT
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