[R] data frame move columns
arnaud Gaboury
arnaud.gaboury at gmail.com
Wed Apr 28 17:34:50 CEST 2010
TY david. Here we go with a correct code!
> -----Original Message-----
> From: David Winsemius [mailto:dwinsemius at comcast.net]
> Sent: Wednesday, April 28, 2010 5:28 PM
> To: arnaud Gaboury
> Cc: r-help at r-project.org
> Subject: Re: [R] data frame move columns
>
>
> On Apr 28, 2010, at 11:14 AM, arnaud Gaboury wrote:
>
> > Dear group,
> >
> > Here is my df:
> >
> > avprix <-
> > structure(list(DESCRIPTION = c("CORN Jul/10", "CORN May/10",
> > "ROBUSTA COFFEE (10) Jul/10", "SOYBEANS Jul/10", "SPCL HIGH GRADE
> > ZINC USD",
> >
> > "STANDARD LEAD USD"), prix = c(-1.5, -1082, 11084, 1983.5, -2464,
> > -118), quantity = c(0, -3, 8, 2, -1, 0), fees = c(-8.64, -30.24,
> > -26.4, -25.92, -37.5, -25)), .Names = c("DESCRIPTION", "prix",
> > "quantity", "fees"), row.names = c(NA, -6L), class = "data.frame")
> >
> > I want to group together all the rows with quantity=0.
> >
> > This following line does the job :
> >
> >> avprix<-rbind(,avprix[avprix$quantity==0,]).
> >
> > I was just wandering if there is a more "academic" way to write it?
>
> ? order
>
> avprix[order(avprix$quantity),]
>
> Or if you want them at the end ... since TRUE > FALSE:
>
> avprix[order(avprix$quantity==0),]
>
> >
> > TY for advice.
> >
> > ______________________________________________
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> > PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> > and provide commented, minimal, self-contained, reproducible code.
>
> David Winsemius, MD
> West Hartford, CT
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