[R] Heatmap without levelplot
Uwe Ligges
ligges at statistik.tu-dortmund.de
Tue May 5 19:56:06 CEST 2009
Antje wrote:
> Hi Uwe,
>
> I tried to explain my problem with the given example.
> I don't see any documentation which tells me that the length of
> "col.regions" should be one less than "at". (At least I assume now that
> it should be this way...)
> If it's equal or longer some colors (in the middle of the color-vector)
> are simply not used.
> Just try the example below with rainbow(5) and rainbow(6) and compare
> the results... both plot will use 5 colors!
> Sorry, but this behaviour is not really self-explaining to me... maybe
> I'm to blind to find the documentation which says that only one color
> less will ensure the usage of all colors.
Well, of you have 5 at locations (i.e. breaks), then you have 4
intervals in between and that's the amount of colors that is sensible.
> (It is so important for me because I need to display a heatmap with
> colors let's say
> * all lower data outliers "green",
> * all higher data outliers "blue" and
> * everything else within the color range "yellow" to "red".
> I've seen that some values do not get blue or green though they are
> outliers...
> I've attached one graph, I've generated - maybe it helps to understand)
>
> Any wrong assumption?
Maybe:
Say you want everything below -1 be considered as a lower outlier and
all above 1 is a higher outlier, then you can say:
levelplot(matrix(c(1,2,0,-2), nrow=2),
at = c(-Inf, seq(-1, 1, length=10), Inf),
col.regions = c(rgb(0,1,0),
hcl(seq(20, 80, length=10), c=400),
rgb(0,0,1)))
Then below -1 is green (rgb(0,1,0)), above 1 is blue (rgb(0,0,1)) and in
between we have 10 regions from -1 to 1 each with a color between some
kind of yellow and red in hcl() space.
Uwe Ligges
> Ciao,
> Antje
>
>
> Uwe Ligges schrieb:
>>
>>
>> Antje wrote:
>>> Hi there,
>>>
>>> as I'm not sure to understand the coloring levelplot uses, I'm
>>> looking for another easy way to create a heatmap like this:
>>>
>>> library(lattice)
>>> mat <- matrix(seq(1,5, length.out = 12), nrow = 3)
>>> mat[1,2] <- 3.5
>>>
>>> my.at <- seq(0.5,5.5, length.out = 6)
>>> my.col.regions <- rainbow(5)
>>>
>>> graph <- levelplot(t(mat[nrow(mat):1, ] ), at = my.at, col.regions =
>>> my.col.regions)
>>> print(graph)
>>>
>>> Can anybody help me with some hints or little examples?
>>
>>
>> Dear Antje,
>>
>> since you are asking the same question again now, maybe you can
>> explain what you are going to get? In fact, I do not undertsand where
>> your problem is. R places the colors according to the values in your
>> matrix very well including the legend and I thought up to today that
>> the plot is self explaining.
>>
>> Best wishes,
>> Uwe Ligges
>>
>>
>>
>>
>>> Antje
>>>
>>> ______________________________________________
>>> R-help at r-project.org mailing list
>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>> PLEASE do read the posting guide
>>> http://www.R-project.org/posting-guide.html
>>> and provide commented, minimal, self-contained, reproducible code.
>>
>
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