[R] Extracting File Basename without Extension

[Gabor Grothendieck]

On Fri, Jan 9, 2009 at 6:52 AM, Wacek Kusnierczyk
<Waclaw.Marcin.Kusnierczyk at idi.ntnu.no> wrote:
> Berwin A Turlach wrote:
>> G'day all,
>>
>> On Fri, 9 Jan 2009 08:12:18 -0200
>> "Henrique Dallazuanna" <wwwhsd at gmail.com> wrote:
>>
>>
>>> Try this also:
>>>
>>> substr(basename(myfile), 1, nchar(basename(myfile)) - 4)
>>>
>>
>> Or, in case that the extension has more than three letters or "myfile"
>> is a vector of names:
>>
>> R> myfile <- "path1/path2/myoutput.txt"
>> R> sapply(strsplit(basename(myfile),"\\."), function(x) paste(x[1:(length(x)-1)], collapse="."))
>> [1] "myoutput"
>> R> myfile2 <- c(myfile, "path2/path3/myoutput.temp")
>> R> sapply(strsplit(basename(myfile2),"\\."), function(x) paste(x[1:(length(x)-1)], collapse="."))
>> [1] "myoutput" "myoutput"
>> R> myfile3 <- c(myfile2, "path4/path5/my.out.put.xls")
>> R> sapply(strsplit(basename(myfile3),"\\."), function(x) paste(x[1:(length(x)-1)], collapse="."))
>> [1] "myoutput"   "myoutput"   "my.out.put"
>>
>>
>
> or have sub do the job for you:
>
> filenames.ext = c("foo.bar", basename("foo/bar/hello.dolly"))
> (filenames.noext = sub("[.][^.]*$", "", filenames.ext, perl=TRUE))

We can omit perl = TRUE here.