[R] Extracting File Basename without Extension

[Wacek Kusnierczyk]

Berwin A Turlach wrote:
> G'day all,
>
> On Fri, 9 Jan 2009 08:12:18 -0200
> "Henrique Dallazuanna" <wwwhsd at gmail.com> wrote:
>
>   
>> Try this also:
>>
>> substr(basename(myfile), 1, nchar(basename(myfile)) - 4)
>>     
>
> Or, in case that the extension has more than three letters or "myfile"
> is a vector of names:
>
> R> myfile <- "path1/path2/myoutput.txt"
> R> sapply(strsplit(basename(myfile),"\\."), function(x) paste(x[1:(length(x)-1)], collapse="."))
> [1] "myoutput"
> R> myfile2 <- c(myfile, "path2/path3/myoutput.temp")
> R> sapply(strsplit(basename(myfile2),"\\."), function(x) paste(x[1:(length(x)-1)], collapse="."))
> [1] "myoutput" "myoutput"
> R> myfile3 <- c(myfile2, "path4/path5/my.out.put.xls")
> R> sapply(strsplit(basename(myfile3),"\\."), function(x) paste(x[1:(length(x)-1)], collapse="."))
> [1] "myoutput"   "myoutput"   "my.out.put"
>
>   

or have sub do the job for you:

filenames.ext = c("foo.bar", basename("foo/bar/hello.dolly"))
(filenames.noext = sub("[.][^.]*$", "", filenames.ext, perl=TRUE))



vQ