[R] sort a data matrix by all the values and keep the names

[hadley wickham]

Hmm, maybe it only works in my development version (to be released v. v. soon)

Hadley

On Mon, Sep 22, 2008 at 8:02 PM, Steven McKinney <smckinney at bccrc.ca> wrote:
> Is something missing in the melt()?
>
>> x<-data.frame(x1=c(1,7),x2=c(4,6),x3=c(8,2))
>> require("reshape")
> Loading required package: reshape
>> dfm <- melt(x, id = c())
> Error in if (!missing(id.var) && !(id.var %in% varnames)) { :
>  missing value where TRUE/FALSE needed
>> dfm[order(dfm$value), ]
> Error: object "dfm" not found
>> x
>  x1 x2 x3
> 1  1  4  8
> 2  7  6  2
>> melt(x, id = c())
> Error in if (!missing(id.var) && !(id.var %in% varnames)) { :
>  missing value where TRUE/FALSE needed
>>
>
>
> Steve McKinney
>
>
> -----Original Message-----
> From: r-help-bounces at r-project.org on behalf of hadley wickham
> Sent: Mon 9/22/2008 5:47 PM
> To: zhihuali
> Cc: r-help at stat.math.ethz.ch
> Subject: Re: [R] sort a data matrix by all the values and keep the names
>
> On Mon, Sep 22, 2008 at 6:54 PM, zhihuali <lzhtom at hotmail.com> wrote:
>>
>> Dear all,
>>
>> If I have a data frame  x<-data.frame(x1=c(1,7),x2=c(4,6),x3=c(8,2)):
>>   x1  x2  x3
>>   1     4  8
>>   7     6  2
>>
>> I want to sort the whole data and get this:
>> x1 1
>> x3  2
>> x2  4
>> x2  6
>> x1   7
>> x3   8
>>
>>  If I do sort(X), R reports:
>> Error in order(list(x1 = c(1, 7), x2 = c(4, 6), x3 = c(8, 2)), decreasing = FALSE) :
>>  unimplemented type 'list' in 'orderVector1'
>>
>> The only way I can sort all the data is by converting it to a matrix:
>>> sort(as.matrix(x))
>> [1] 1 2 4 6 7 8
>>
>> But now I lost all the names attributes.
>>
>> Is it possible to sort a data frame and keep all the names?
>
> Here's one way:
>
> dfm <- melt(x, id = c())
> dfm[order(dfm$value), ]
>
> Hadley
>
> --
> http://had.co.nz/
>
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