[R] sort a data matrix by all the values and keep the names

[Steven McKinney]

Is something missing in the melt()?

> x<-data.frame(x1=c(1,7),x2=c(4,6),x3=c(8,2))
> require("reshape")
Loading required package: reshape
> dfm <- melt(x, id = c())
Error in if (!missing(id.var) && !(id.var %in% varnames)) { : 
  missing value where TRUE/FALSE needed
> dfm[order(dfm$value), ]
Error: object "dfm" not found
> x
  x1 x2 x3
1  1  4  8
2  7  6  2
> melt(x, id = c())
Error in if (!missing(id.var) && !(id.var %in% varnames)) { : 
  missing value where TRUE/FALSE needed
>


Steve McKinney


-----Original Message-----
From: r-help-bounces at r-project.org on behalf of hadley wickham
Sent: Mon 9/22/2008 5:47 PM
To: zhihuali
Cc: r-help at stat.math.ethz.ch
Subject: Re: [R] sort a data matrix by all the values and keep the names
 
On Mon, Sep 22, 2008 at 6:54 PM, zhihuali <lzhtom at hotmail.com> wrote:
>
> Dear all,
>
> If I have a data frame  x<-data.frame(x1=c(1,7),x2=c(4,6),x3=c(8,2)):
>   x1  x2  x3
>   1     4  8
>   7     6  2
>
> I want to sort the whole data and get this:
> x1 1
> x3  2
> x2  4
> x2  6
> x1   7
> x3   8
>
>  If I do sort(X), R reports:
> Error in order(list(x1 = c(1, 7), x2 = c(4, 6), x3 = c(8, 2)), decreasing = FALSE) :
>  unimplemented type 'list' in 'orderVector1'
>
> The only way I can sort all the data is by converting it to a matrix:
>> sort(as.matrix(x))
> [1] 1 2 4 6 7 8
>
> But now I lost all the names attributes.
>
> Is it possible to sort a data frame and keep all the names?

Here's one way:

dfm <- melt(x, id = c())
dfm[order(dfm$value), ]

Hadley

-- 
http://had.co.nz/

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