[R] lapply where each list object has multiple parts

[Patrick Burns]

The function in 'lapply' gets each component, so
write a function that does what you want given a
component of the list:

lapply(BigList, function(x) mean(x$label1))

Patrick Burns
patrick at burns-stat.com
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of S Poetry and "A Guide for the Unwilling S User")

eric lee wrote:
> Hi.  I have a list where each object in the list has multiple parts.  I'd
> like to take the mean of just one part of each object.  Is it possible to do
> this with lapply?  If not, can you recommend another function?  Thanks.
>
> eric
>
>   
>> x1 <- c(0,1,2,3)
>> x2 <- c(7,8)
>> x3 <- c(2,6,6,8)
>> x4 <- c(4,8)
>>
>> Lst1 <- list(label1 = x1,label2 = x2)
>> Lst2 <- list(label1 = x3, label2 = x4)
>>
>> BigList <- list(Lst1, Lst2)
>>
>> lapply(BigList$label1, mean)
>>     
> list()
>   
>
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