[R] lapply where each list object has multiple parts
Chunhao Tu
tu_chunhao at yahoo.com
Thu Oct 2 05:23:41 CEST 2008
Hi Eric,
> data<-list(x1 <- c(0,1,2,3),x2 <- c(7,8),x3 <- c(2,6,6,8), x4 <- c(4,8))
> lapply(X=data, mean)
[[1]]
[1] 1.5
[[2]]
[1] 7.5
[[3]]
[1] 5.5
[[4]]
[1] 6
Hope it helps
Chunhao
eric lee-8 wrote:
>
> Hi. I have a list where each object in the list has multiple parts. I'd
> like to take the mean of just one part of each object. Is it possible to
> do
> this with lapply? If not, can you recommend another function? Thanks.
>
> eric
>
>> x1 <- c(0,1,2,3)
>> x2 <- c(7,8)
>> x3 <- c(2,6,6,8)
>> x4 <- c(4,8)
>>
>> Lst1 <- list(label1 = x1,label2 = x2)
>> Lst2 <- list(label1 = x3, label2 = x4)
>>
>> BigList <- list(Lst1, Lst2)
>>
>> lapply(BigList$label1, mean)
> list()
>>
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>
--
View this message in context: http://www.nabble.com/lapply-where-each-list-object-has-multiple-parts-tp19772755p19772797.html
Sent from the R help mailing list archive at Nabble.com.
More information about the R-help
mailing list