[R] Is there an equivalent * operator?

[john seers (IFR)]

Something like this might do what you want:


dates<-paste(c("2008"), c("Jan", "Feb", "Sep", "Sep", "Dec"), 1:3,
sep="")
temp<-rnorm(length(dates))*30
data1<-data.frame(Dates=dates, Temp=temp)

data.s1<-data1[grep("Sep", data1[["Dates"]]),]

> data.s1
     Dates      Temp
3 2008Sep3 22.263627
4 2008Sep1  9.854643

 
Regards

JS


---

-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org]
On Behalf Of Williams, Robin
Sent: 24 July 2008 11:31
To: r-help at r-project.org
Subject: [R] Is there an equivalent * operator?

Hi all,
Is there an equivalent to the general * operator in R, where * can
represent any character? 
  I have a dataset, one column being date, date ranging between
April-September, 97-06. I would like to be able to acquire the data for
a specific month, say September, so that I can take average temperatures
for the month, etc. I thought I would be able to do something like
data.s1 <- subset(data,date=="**-Sep-**")
data.s1
but when I do
data.s1
I get "0 rows or 0-length row.names". 
  Any idea of a simple way I can perform this task? 
All dates are in the form xx-xxx-xx, EG 30-Sep-06. 
Thanks for any assistance.  
 

Robin Williams
Met Office summer intern - Health Forecasting
robin.williams at metoffice.gov.uk 

 

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