# [R] a more elegant approach to getting the majority level

Dimitris Rizopoulos dimitris.rizopoulos at med.kuleuven.be
Thu May 26 17:00:23 CEST 2005

```you could try this:

x <- factor(sample(letters[1:3], 20, TRUE))
#######
tab <- table(x)
names(tab)[tab == max(tab)]

I hope it helps.

Best,
Dimitris

----
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven

Tel: +32/16/336899
Fax: +32/16/337015
Web: http://www.med.kuleuven.ac.be/biostat/
http://www.student.kuleuven.ac.be/~m0390867/dimitris.htm

----- Original Message -----
From: "Rajarshi Guha" <rxg218 at psu.edu>
To: "R" <r-help at stat.math.ethz.ch>
Sent: Thursday, May 26, 2005 4:36 PM
Subject: [R] a more elegant approach to getting the majority level

> Hi, I have a factor and I would like to find the most frequent
> level.
>
> I think my current approach is a bit long winded and I was wondering
> if
> there was a more elegant way to do it:
>
> x <- factor(sample(1:0, 5,replace=TRUE))
>
> levels(x)[ which( as.logical((table(x) == max(table(x)))) ==
> TRUE ) ]
>
> (The length of x will always be an odd number, so I wont get a tie
> in
> max())
>
> Thanks,
>
> -------------------------------------------------------------------
> Rajarshi Guha <rxg218 at psu.edu> <http://jijo.cjb.net>
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> -------------------------------------------------------------------
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