[R] a more elegant approach to getting the majority level

[Uwe Ligges]

Rajarshi Guha wrote:

> Hi, I have a factor and I would like to find the most frequent level.
> 
> I think my current approach is a bit long winded and I was wondering if
> there was a more elegant way to do it:
> 
> x <- factor(sample(1:0, 5,replace=TRUE))
> 
> levels(x)[ which( as.logical((table(x) == max(table(x)))) == TRUE ) ]

(== TRUE) can ALWAYS be omitted, see also:
  library(fortunes)
  fortune("TRUE")

x == max(x) should be replaced by which.max(x)

as.logical() is superfluous


Hence we get:
   names(which.max(table(x)))

Uwe Ligges



> (The length of x will always be an odd number, so I wont get a tie in
> max())
> 
> Thanks,
> 
> -------------------------------------------------------------------
> Rajarshi Guha <rxg218 at psu.edu> <http://jijo.cjb.net>
> GPG Fingerprint: 0CCA 8EE2 2EEB 25E2 AB04 06F7 1BB9 E634 9B87 56EE
> -------------------------------------------------------------------
> Alcohol, an alternative to your self
> - 'Alcohol' by the Bare Naked Ladies
> 
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html