[R] tapply and NA value

[Leonardo Lami]

Thanks very much!
Best of all,
Leonardo


Alle 10:52, venerdì 25 marzo 2005, Dimitris Rizopoulos ha scritto:
> you should look at the 'na.rm=FALSE' argument of '?mean()', i.e.,
>
> x <- rnorm(100); x[sample(100, 10)] <- NA
> f <- sample(letters[1:5], 100, TRUE)
> ###############
> tapply(x, f, mean)
> tapply(x, f, mean, na.rm=TRUE)
>
>
> I hope it helps.
>
> Best,
> Dimitris
>
> ----
> Dimitris Rizopoulos
> Ph.D. Student
> Biostatistical Centre
> School of Public Health
> Catholic University of Leuven
>
> Address: Kapucijnenvoer 35, Leuven, Belgium
> Tel: +32/16/336899
> Fax: +32/16/337015
> Web: http://www.med.kuleuven.ac.be/biostat/
>      http://www.student.kuleuven.ac.be/~m0390867/dimitris.htm
>
>
> ----- Original Message -----
> From: "Leonardo Lami" <lami at faunalia.it>
> To: <r-help at stat.math.ethz.ch>
> Sent: Friday, March 25, 2005 10:35 AM
> Subject: [R] tapply and NA value
>
> > Hi,
> > I'm writing for a little help.
> > I have a dataframe with same NA value and I'd like to obtain the
> > means of the
> > value of a coloumn grouped by the levels of a factor coloumn of the
> > datframe.
> > I'm using the function "tapply" but I see that if only a NA value is
> > present
> > the result is NA.
> > There is an option to have the correct result or I must use an other
> > function?
> >
> > Thanks of all
> > Leonardo
> > --
> > Leonardo Lami
> > lami at faunalia.it            www.faunalia.it
> > Via Colombo 3 - 51010 Massa e Cozzile (PT), Italy   Tel:
> > (+39)349-1310164
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> > https://www.biglumber.com
> >
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-- 
Leonardo Lami
lami at faunalia.it            www.faunalia.it
Via Colombo 3 - 51010 Massa e Cozzile (PT), Italy   Tel: (+39)349-1310164
GPG key @: hkp://wwwkeys.pgp.net http://www.pgp.net/wwwkeys.html
https://www.biglumber.com