[R] How to get variable names in a function?
Heinz Tuechler
tuechler at gmx.at
Wed Feb 9 08:18:16 CET 2005
At 19:26 08.02.2005 -0500, Liaw, Andy wrote:
>Here's a (rather ugly) function that takes its arguments and turn them into
>a list, using the names of the arguments and the names of the components:
>
>listWithName <- function(...) {
> aname <- sapply(as.list(substitute({...})[-1]), deparse)
> res <- list(...)
> names(res) <- aname
> res
>}
>
>Here are a couple of examples:
>
>> x <- runif(5)
>> y <- "abc"
>> listWithName(x, y)
>$x
>[1] 0.44241647 0.07540958 0.46405311 0.01684738 0.94370893
>
>$y
>[1] "abc"
>
>> listWithName(x, 1:3, y)
>$x
>[1] 0.44241647 0.07540958 0.46405311 0.01684738 0.94370893
>
>$"1:3"
>[1] 1 2 3
>
>$y
>[1] "abc"
>
>> listWithName(abc=x, y)
>$x
>[1] 0.44241647 0.07540958 0.46405311 0.01684738 0.94370893
>
>$y
>[1] "abc"
>
>You can then use lapply() on the output. lapply() will automatically attach
>names to the components of its output.
>
>Andy
>
Thank you very much, this looks promising to me. As soon as possible I will
try to apply it to my problem.
Heinz
>
>> From: Heinz Tuechler
>>
>> At 10:32 08.02.2005 -0800, Berton Gunter wrote:
>> >If you pass your function a NAMED list, then the following works:
>> >
>> >demofn<-function(varlist)
>> >{
>> > nm<-names(varlist)
>> > for (i in seq(along=varlist))
>> > {cat('\n',nm[i])
>> > print(table(varlist[[i]]))
>> > }
>> >}
>> >demofn(list(bravo=bravo, charly=charly))
>> >
>> >If you don't pass a named list, then you need to restrict
>> and know the form
>> >of the expression that is the varlist argument in order to
>> substitute() and
>> >deparse it correctly to get the identifiers you want. For
>> example, if you
>> >knew that varlist were an expression of the form:
>> >list(var1,var2,var3,...)
>> >then you could get the ith identifier vari via:
>> >
>> >deparse((as.list(substitute(varlist))[-1])[[i]])
>> >
>> >HOWEVER, this is probably inefficient and **clearly**
>> clumsy, undesirable,
>> >and almost certain to fail (so don't do this!).
>> >
>> >If the number of tables is small enough that you could
>> simply list them as
>> >arguments (as opposed to constructing the list of vectors to
>> be tabled in
>> >some way), then the function call could be of the form
>> function(...) and the
>> >... arguments could be processed as discussed in section 3.1
>> of V&R's S
>> >PROGRAMMING. That is, your example call would be of the form:
>> >demofn(bravo,charly), and you can forgo lists in the call
>> altogether. This
>> >strategy actually also works for long constructed lists of
>> arguments using
>> >do.call() -- see it's help file and V&R again for details.
>> >
>> >
>> >-- Bert Gunter
>> >Genentech Non-Clinical Statistics
>> >South San Francisco, CA
>> >
>> >"The business of the statistician is to catalyze the
>> scientific learning
>> >process." - George E. P. Box
>> >
>> Thank you for your detailled answer. I see that it is not as easy as I
>> expected and I will think about a convenient way to do it.
>> I tried also the opposit approach i.e. to pass a vector of
>> names to the
>> function like c("bravo", "charly") but until now I did not
>> solve it either.
>> A third way worked, but seemed to me less generally applicable.
>> I stored all the names of the variables of a data.frame in a
>> vector, made
>> the selection of the variables by match() and passed the
>> indices of the
>> selected variables to the function. By this method I can then
>> access each
>> variable by its index and also its name via the vector of the
>> stored names.
>> It seemed to me a crude method of a beginner like me and I
>> still hope to
>> find a better one.
>> Your suggestion with the named list may be the best, if I
>> find a practical
>> way to produce this named list by some function from a simple
>> list without
>> retyping each name.
>>
>> Thanks again,
>>
>> Heinz
>> >
>> >
>> >> -----Original Message-----
>> >> From: r-help-bounces at stat.math.ethz.ch
>> >> [mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of
>> Heinz Tuechler
>> >> Sent: Tuesday, February 08, 2005 8:45 AM
>> >> To: r-help at stat.math.ethz.ch
>> >> Subject: [R] How to get variable names in a function?
>> >>
>> >> Hello,
>> >>
>> >> applying a function to a list of variables I face the
>> >> following problem:
>> >> Let's say I want to compute tables for several variables. I
>> >> could write a
>> >> command for every single table, like
>> >> bravo<-c(1,1,2,3,5,5,5,);charly<-c(7,7,4,4,2,1)
>> >> table(bravo); table(charly)
>> >> > table(bravo); table(charly)
>> >> bravo
>> >> 1 2 3 5
>> >> 2 1 1 3
>> >> charly
>> >> 1 2 4 7
>> >> 1 1 2 2
>> >> The results are two tables with the names of the variables
>> above each.
>> >> If I want to do the same thing by a function I find no way
>> to get the
>> >> variable names above the tables.
>> >> demofn<-function(varlist)
>> >> {for (i in seq(along=varlist))
>> >> {cat(deparse(varlist[i])) # < - - - - how to change this?
>> >> print(table(varlist[i]))}}
>> >> > demofn(list(bravo, charly))
>> >> list(c(1, 1, 2, 3, 5, 5, 5))
>> >> 1 2 3 5
>> >> 2 1 1 3
>> >> list(c(7, 7, 4, 4, 2, 1))
>> >> 1 2 4 7
>> >> 1 1 2 2
>> >> >
>> >>
>> >> Thanks,
>> >> Heinz Tüchler
>> >>
>> >> ______________________________________________
>> >> R-help at stat.math.ethz.ch mailing list
>> >> https://stat.ethz.ch/mailman/listinfo/r-help
>> >> PLEASE do read the posting guide!
>> >> http://www.R-project.org/posting-guide.html
>> >>
>> >
>> >
>> >
>>
>> ______________________________________________
>> R-help at stat.math.ethz.ch mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide!
>> http://www.R-project.org/posting-guide.html
>>
>>
>
>
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