[R] Summary: do.call and environments
Thomas Petzoldt
petzoldt at rcs.urz.tu-dresden.de
Thu Mar 11 08:22:45 CET 2004
Dear R users,
thank you very much for your suggestions. I've learned much, especially
that the problem was not as simple as I thought. There have been several
proposals, but most of them solved the problem only partly.
The proposal(s) of Gabor and Tony (different versions) seemed to be very
promising:
> fx <- function(y) print(x*y)
> f <- function(fun, x) {
> environment(fun) <- environment()
> fun(3)
> }
> f(fx,2)
... but unfortunately they miss the "do.call" mechanism. I intended to
call a function given as character with f("fx", value), and not f(fx,
value).
Another proposal (from Robert Gentleman, thank you) works. It has the
only disadvantage, that I have to set an environment outside of my own
function. If I understand this correctly, this means that the new
environment ist set persistently (*globally*) and may have side-effects
to other calls:
> fx <- function(y) print(x*y)
> environment(fx) <- new.env()
>
> ff <- function(fun, x) {
> assign("x", x, environment(get(fun, mode="function")))
> do.call(fun, list(y=3))
> }
Furthermore, Andy pointed out that my idea was a bad one, but why I am
trying such weired things? My problem is, that I want to define list
objects which contain informations, about how they are processed (as
character, not as copy of a function). This solver function (e.g.
"lsoda" from the odesolve package) then calls a third function (my model
equations), provided from my side again, but unfortunately does not
"pass through" some additonal argument(s), needed by the model
equations. So I wanted to call lsoda or my own function provided with
the additional arguments within an own environment.
Now, as it comes out, that this was really a bad idea, I should focus on
the pass-trough method (...) and use one of the 99% workarounds
mentioned above in the meantime.
Thank you again
Thomas P.
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