[R] Help with acf

[Prof Brian Ripley]

On Thu, 8 Jan 2004, Stephen Opiyo wrote:

> I would like to get the result of acf min of lag 2 and max of lag 50. 
>  When I use time series  ( acf,  lag.max = 50, type="covariance"),  I 
> got lag 0 to lag 50.  How do I get lag 2 to lag 50?

Subset the answer in the standard way, as in:

data(Nile)
acf(Nile, lag.max = 50, type="covariance", plot=F)$acf[3:51,,]

-- 
Brian D. Ripley,                  ripley at stats.ox.ac.uk
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford,             Tel:  +44 1865 272861 (self)
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