[R] treatment contrasts and summary.lm
Berton Gunter
gunter.berton at gene.com
Thu Dec 2 17:13:47 CET 2004
?C ?contr.treatment may help. Also 6.2 of Venables's and Ripley's MASS for
a more thorough discussion.
The coefficients are the differences between the mean at the stated levels
of the factor and the first level.
-- Bert Gunter
Genentech Non-Clinical Statistics
South San Francisco, CA
"The business of the statistician is to catalyze the scientific learning
process." - George E. P. Box
> -----Original Message-----
> From: r-help-bounces at stat.math.ethz.ch
> [mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of
> Christoph Scherber
> Sent: Thursday, December 02, 2004 3:01 AM
> To: R-help at stat.math.ethz.ch
> Subject: [R] treatment contrasts and summary.lm
>
> Dear list members,
>
> I have a 2-factor ANOVA where the summary.lm output looks like this
> (using treatment contrasts):
>
> Value Std. Error t value Pr(>|t|)
> (Intercept) 0.0389 0.0220 1.7695 0.0817
> as.factor(Block)1 0.0156 0.0066 2.3597 0.0215
> as.factor(Block)2 -0.0018 0.0037 -0.4857 0.6289
> as.factor(Block)3 -0.0007 0.0026 -0.2812 0.7795
> as.factor(AZ)1 -0.0066 0.0076 -0.8670 0.3893
> as.factor(AZ)2 0.0064 0.0047 1.3530 0.1810
> as.factor(AZ)3 -0.0015 0.0031 -0.4863 0.6284
> as.factor(AZ)4 0.0054 0.0025 2.1499 0.0355
> as.factor(AZ)5 0.0062 0.0037 1.6653 0.1009
>
> Block has 4 levels and AZ has 6 levels. My question now is:
> What exactly
> do the values for AZ show? I know it´s somehow differences between
> intercepts, but it would be great if someone could tell me
> more on how
> exactly to interprete the output.
>
> Thanks very much in advance!
> Christoph
>
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