[R] for loop problem
Douglas Bates
bates at stat.wisc.edu
Tue Mar 4 04:45:04 CET 2003
"Jeremy Z Butler" <jerrytheshrub at hotmail.com> writes:
> Hi,
> I'm just coming to grips with "for" looping etc. and have a bit of a
> problem:
>
>
> I want to generate a sequence which goes
> 1 2 3 4 5 6 7 8 14 15 16 17 18 19 20 21 26 27 ...
> i.e. 8 consecutive numbers then 5 missed then the next 8 numbers etc.
> I was going to do this using the seq() function but couldn't figure
> out how so I thought I'd try a loop:
>
>
> for (x in seq(1,650,13))
> { num.set.1 <- x:x+8
> }
> but now what I need to do is write code such that each time it goes
> through the loop it assigns the output to a different object
> e.g. num.set.1 on the first loop then num.set.2 on the next etc. so
> that they can be concatenated. Is there any way to do this??
>
>
> I may be doing this an extremely complicated way but with my zero
> programming experience its the best I can think of. Can anyone help?
I suggest using a matrix.
> mseq = as.vector(matrix(1:650, nrow = 13)[1:8,])
> length(mseq)
[1] 400
> mseq[1:20]
[1] 1 2 3 4 5 6 7 8 14 15 16 17 18 19 20 21 27 28 29 30
More information about the R-help
mailing list