[R] for loop problem
Henrik Bengtsson
hb at maths.lth.se
Tue Mar 4 04:29:17 CET 2003
Your sequence is 1:a + k*(a+b) where a=8, b=5 and k=0,1,...,K. You can
make use of the fact that R loops of vectors if two vectors are not the
same;
a <- 8
b <- 5
K <- 49
x <- rep((0:K)*(a+b), each=a) + 1:a
Cheers
Henrik Bengtsson
> -----Original Message-----
> From: r-help-admin at stat.math.ethz.ch
> [mailto:r-help-admin at stat.math.ethz.ch] On Behalf Of Jeremy Z Butler
> Sent: den 4 mars 2003 14:14
> To: r-help at stat.math.ethz.ch
> Subject: [R] for loop problem
>
>
> Hi,
> I'm just coming to grips with "for" looping etc. and have a bit of a
> problem:
>
> I want to generate a sequence which goes
> 1 2 3 4 5 6 7 8 14 15 16 17 18 19 20 21 26 27 ...
> i.e. 8 consecutive numbers then 5 missed then the next 8
> numbers etc. I was going to do this using the seq() function
> but couldn't figure out how
> so I thought I'd try a loop:
>
> for (x in seq(1,650,13))
> { num.set.1 <- x:x+8
> }
> but now what I need to do is write code such that each time
> it goes through
> the loop it assigns the output to a different object e.g.
> num.set.1 on the
> first loop then num.set.2 on the next etc. so that they can
> be concatenated.
> Is there any way to do this??
>
> I may be doing this an extremely complicated way but with my zero
> programming experience its the best I can think of. Can anyone help?
>
> J
>
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