[R] for loop problem

[Henrik Bengtsson]

Your sequence is 1:a + k*(a+b) where a=8, b=5 and k=0,1,...,K. You can
make use of the fact that R loops of vectors if two vectors are not the
same;

  a <- 8
  b <- 5
  K <- 49
  x <- rep((0:K)*(a+b), each=a) + 1:a

Cheers

Henrik Bengtsson

> -----Original Message-----
> From: r-help-admin at stat.math.ethz.ch 
> [mailto:r-help-admin at stat.math.ethz.ch] On Behalf Of Jeremy Z Butler
> Sent: den 4 mars 2003 14:14
> To: r-help at stat.math.ethz.ch
> Subject: [R] for loop problem
> 
> 
> Hi,
> I'm just coming to grips with "for" looping etc. and have a bit of a 
> problem:
> 
> I want to generate a sequence which goes
> 1 2 3 4 5 6 7 8 14 15 16 17 18 19 20 21 26 27 ...
> i.e. 8 consecutive numbers then 5 missed then the next 8 
> numbers etc. I was going to do this using the seq() function 
> but couldn't figure out how 
> so I thought I'd try a loop:
> 
> for (x in seq(1,650,13))
> { num.set.1 <- x:x+8
> }
> but now what I need to do is write code such that each time 
> it goes through 
> the loop it assigns the output to a different object e.g. 
> num.set.1 on the 
> first loop then num.set.2 on the next etc. so that they can 
> be concatenated. 
> Is there any way to do this??
> 
> I may be doing this an extremely complicated way but with my zero 
> programming experience its the best I can think of. Can anyone help?
> 
> J
> 
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list 
> http://www.stat.math.ethz.ch/mailman/listinfo/> r-help
> 
>