[R] replace

[Jeff Gentry]

Following up on my own message, sorry I was just removing NAs, sorry.

> A vector?
> > a <- c(1,2,NA,3,4,NA,5,6,NA)
> > a
> [1]  1  2 NA  3  4 NA  5  6 NA

> a[is.na(a)] <- 0
> a
[1] 1 2 0 3 4 0 5 6 0

> A list?
> > a <- list(1,2,3,NA,4,5,NA,6,NA,7)
> a <- lapply(a,function(x){if(is.na(x))return(0) else(return(x))})
> a 
[[1]]
[1] 1

[[2]]
[1] 2

[[3]]
[1] 3

[[4]]
[1] 0

[[5]]
[1] 4

[[6]]
[1] 5

[[7]]
[1] 0

[[8]]
[1] 6

[[9]]
[1] 0

[[10]]
[1] 7


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