[R] ifelse ?

[Liaw, Andy]

The following seems to do what you want:

fuz <- function(x) {
  x.range <- quantile(x, c(.15, .85))
  x[x < x.range[1]] <- x.range[1]
  x[x > x.range[2]] <- x.range[2]
  x <- (x - x.range[1]) / (x.range[2] - x)
  x
}

HTH,
Andy

-----Original Message-----
From: Christian Schulz [mailto:ozric at web.de]
Sent: Monday, December 09, 2002 10:23 AM
To: r-help at stat.math.ethz.ch
Subject: [R] ifelse ?


Hi,

i want transform data and using apply(data,2,fuz)
, but i don't know why the values   < low  &  > high  don't get 0 or 1, they
get
the value from Formula ,too  "((x-low)/(high-low))"  what's not the
intention ?

....is switch more approriate !?

thanks for advance ,Christian

fuz <- function (x) {
#x <- na.omit(x)
low <- quantile(x,0.15)[[1]]
high <- quantile(x,0.85)[[1]]
if (x < low ) zg <- 0
if (x >= low &  x <= high)
zg <- ((x-low)/(high-low))
if (x > high)
zg <- 1
return(zg) }


fuz <- function (x) {
#x <- na.omit(x)
low <- quantile(x,0.15)[[1]]
high <- quantile(x,0.85)[[1]]
ifelse(x < low,0,(x-low)/(high-low))
ifelse (x > high,1,(x-low)/(high-low))}

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