[R] Easy way?

Martin Maechler maechler at stat.math.ethz.ch
Mon Jun 26 10:14:56 CEST 2000

>>>>> "Uwe" == Uwe Ligges <ligges at statistik.uni-dortmund.de> writes:

    >> Yves Gauvreau wrote:
    >> Hi,
    >> Say I have this vector x <- sort(rnorm(n)). I'd like to know if
    >> there is a nice way to find out the index of the nearest x to say
    >> 1.5?

    Uwe> I would try: 
	 which(abs(x - 1.5) == min(abs(x - 1.5)))

(and Jan Schelling gives the same solution in "modular" steps
 without recomputing   "abs(x - 1.5)".)

This is fine and fast enough for moderate data size.
However, since version 1.1 

help(which) has

  >> See Also:
  >>      `Logic', `which.min' for the index of the minimum or maximum.
and  which.min(), which.max() are really the functions you want to use

Martin Maechler <maechler at stat.math.ethz.ch>	http://stat.ethz.ch/~maechler/
Seminar fuer Statistik, ETH-Zentrum  LEO D10	Leonhardstr. 27
ETH (Federal Inst. Technology)	8092 Zurich	SWITZERLAND
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