[R] "formula plotting" -> substitute pecularity
Martin Maechler
maechler at stat.math.ethz.ch
Tue Dec 14 18:27:36 CET 1999
This is something between a question and a bug report.
{sometimes one should first ask on R-help before sending to R-bugs....}
I wanted to plot (.) a formula with "..."
## Works :
e0 <- expression(T(x[1],...x[n])*", "*N[1] == 101) # works ok
plot(1, main = e0)
## Now, need substitute, to replace with value of variableThis works
nn <- 102
(e1 <- substitute(T(x[1],...x[n])*", "*N[1] == n1, list(n1=nn)))
plot(1,main=e1)
## this works, but only because of a typo: I forgot one ","
## This ``should'' work, but does not :
e2 <- substitute(T(x[1],...,x[n])*", "*N[1] == n1, list(n1=nn))
##>> Error: ... used in an incorrect context
--
Martin Maechler <maechler at stat.math.ethz.ch> http://stat.ethz.ch/~maechler/
Seminar fuer Statistik, ETH-Zentrum LEO D10 Leonhardstr. 27
ETH (Federal Inst. Technology) 8092 Zurich SWITZERLAND
phone: x-41-1-632-3408 fax: ...-1228 <><
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