[R-sig-teaching] Plot f(x) = x^(1/5)

Steven Stoline sstoline at gmail.com
Tue May 17 15:06:45 CEST 2016


Dear All:

in my TI-Calculator (-0.5)^(1/5) = -0.8705, but in R  (-0.5)^(1/5) = NaN.


with thanks
steve

On Tue, May 17, 2016 at 8:52 AM, jim holtman <jholtman at gmail.com> wrote:

> System is working correctly.  A negative number cannot be raised to a
> fractional power:
>
> > (-2)^(1/5)
> [1] NaN
>
>
>
>
> Jim Holtman
> Data Munger Guru
>
> What is the problem that you are trying to solve?
> Tell me what you want to do, not how you want to do it.
>
> On Tue, May 17, 2016 at 8:44 AM, Steven Stoline <sstoline at gmail.com>
> wrote:
>
>> Dear All:
>>
>>
>> I am trying to plot the function f(x) = x^(1/5) for x=seq(-2,2,0.01). It
>> give me only the plot of f(x) for the positive part of x. I checked the
>> values of f(x), it is NaN for all negative values of x.
>>
>> *this is my code:*
>>
>>
>> x<-seq(-2,2,0.01)
>> y<- (x)^(1/5)
>> plot(x,y, type="l", lwd=3, xlab = " ", ylab = " ", col="blue")
>> abline(v=0, col="gray", lty=2, lwd=3)
>> abline(h=0, col="gray", lty=2, lwd=3)
>>
>>
>>
>> any help will be appreciated.
>>
>>
>> with many thanks
>> steve
>> --
>> Steven M. Stoline
>> 1123 Forest Avenue
>> Portland, ME 04112
>> sstoline at gmail.com
>>
>>         [[alternative HTML version deleted]]
>>
>> _______________________________________________
>> R-sig-teaching at r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-sig-teaching
>>
>
>


-- 
Steven M. Stoline
1123 Forest Avenue
Portland, ME 04112
sstoline at gmail.com

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