[R-sig-ME] order of models when using anova

[Steve Taylor]

Both ways work.  I think anova() is smart enough to figure out which model is the smaller one.

library(lme4)
example(glmer)
# Compare these outputs...
anova(gm1,gm2)
anova(gm2,gm1)

cheers,
     Steve
____________________________________________

Steve Taylor
   Biostatistician
   Faculty of Health and Environmental Sciences
   AUT University
   http://www.aut.ac.nz/profiles/steve-taylor
____________________________________________

-----Original Message-----
From: r-sig-mixed-models-bounces at r-project.org [mailto:r-sig-mixed-models-bounces at r-project.org] On Behalf Of Juliet Hannah
Sent: Friday, 21 February 2014 5:22a
To: r-sig-mixed-models at r-project.org
Subject: [R-sig-ME] order of models when using anova

All,

When using the anova command to compare nested models I thought the order was

anova(reduced model, full model)

Where the 'full model' has more terms.


However, looking at the slides on:

http://lme4.r-forge.r-project.org/slides/2009-07-21-Seewiesen/6Interactions-4a4.pdf


pg 3 (comparing the model fits), it looks like I had this backward.

Did I have it backward, or is lme4 different, or is the order not important?

Thanks,

Juliet

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