[R-sig-ME] cross-over design

[ONKELINX, Thierry]

lmer(TGA ~ Treatment + Time + (1|sub) ,family=binomial) is the correct syntax

Best regards,

Thierry
----------------------------------------------------------------------------
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek
team Biometrie & Kwaliteitszorg
Gaverstraat 4
9500 Geraardsbergen
Belgium

Research Institute for Nature and Forest
team Biometrics & Quality Assurance
Gaverstraat 4
9500 Geraardsbergen
Belgium

tel. + 32 54/436 185
Thierry.Onkelinx at inbo.be
www.inbo.be

To call in the statistician after the experiment is done may be no more than asking him to perform a post-mortem examination: he may be able to say what the experiment died of.
~ Sir Ronald Aylmer Fisher

The plural of anecdote is not data.
~ Roger Brinner

The combination of some data and an aching desire for an answer does not ensure that a reasonable answer can be extracted from a given body of data.
~ John Tukey
  

> -----Oorspronkelijk bericht-----
> Van: r-sig-mixed-models-bounces at r-project.org 
> [mailto:r-sig-mixed-models-bounces at r-project.org] Namens Soyeon Ahn
> Verzonden: woensdag 16 februari 2011 10:11
> Aan: r-sig-mixed-models at r-project.org
> Onderwerp: [R-sig-ME] cross-over design
> 
> Dear all,
> 
> I have a repeated binary measurements and can't figure out 
> how my data will work.
> Response (dependent, Y/N) was repeatedly recorded across Time 
> (categorical : 3 time points) with different Treatments (categorical :
> 2 levels).
> The problem is that each subject was only assigned either the 
> first or the second time point. All were assigned into the 
> third time point, though. Thus, it seems to me that Subject 
> (random) is cross-over withn Time (fixed) effect.
> 
> For example,
> 
>     	    Treatment	 Time	Res
> sub1	    A		 1	Y
> sub1	    B		 1	N
> sub1	    A		 3	Y
> sub1	    B		 3	Y
> 
> sub2	    A		 2	Y
> sub2	    B		 2	Y
> sub2	    A		 3	N
> sub2	    B		 3	N
> 
> So far, I have played around the following models and I feel 
> that the fist one produces feasible outcomes, even though the 
> last one seems to be the right syntax.
> 
> lmer(TGA ~ Treatment + Time + (1|Time) ,family=binomial) 
> lmer(TGA ~ Treatment + Time + (1|sub) ,family=binomial) 
> lmer(TGA ~ Treatment + Time + (1|sub) + (1|Time) ,family=binomial)
> 
> Can anyone suggest a solution to this? And please correct me 
> if I'm wrong
> 
> Best,
> 
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