[R-sig-ME] Why am I getting a Variance of 0 for my random effect
Kevin E. Thorpe
kevin.thorpe at utoronto.ca
Wed Aug 11 20:13:22 CEST 2010
Hello.
I'm getting a variance of 0 on a random effect and I don't know why.
I suspect I've not set the model up correctly. My transcript is below
with my own comments sprinkled in for time to time.
A little bit about the data (which I will provide off-list if
requested). We have nurses managing an aspect of patient care
according to different algorithms. Interest focuses on of the
algorithms result in different outcomes. I have restricted this
to only nurses who did each algorithm twice (in case my problem
was being caused by some nurses doing only one algorithm, possibly
only one time).
I figured that since I have multiple observations per nurse, I
should treat nurse as a random effect, but maybe I confused myself
again.
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> library(lattice)
> library(lme4)
> str(data1)
'data.frame': 72 obs. of 3 variables:
$ RN : int 1 1 2 3 7 7 9 9 15 15 ...
$ Assignment: Factor w/ 2 levels "E","N": 1 1 1 1 1 1 1 1 1 1 ...
$ AUChr : num 12.26 7.23 9.26 4.04 10.31 ...
> tmp1 <-
with(data1,aggregate(AUChr,list(RN=RN,Assigment=Assignment),mean))
> names(tmp1)[3] <- "Mean"
>
> tmp2 <-
with(data1,aggregate(AUChr,list(RN=RN,Assignment=Assignment),var))
> names(tmp2)[3] <- "Variance"
>
> meanvar <- merge(tmp1,tmp2)
The point of this is to show that the means are not all the same,
nor are the variances.
> meanvar
RN Assignment Mean Variance
1 1 E 9.745 12.65045
2 1 N 7.185 1.36125
3 15 E 10.605 15.07005
4 15 N 10.385 4.41045
5 16 E 8.175 0.00845
6 16 N 8.420 1.03680
7 2 E 7.300 7.68320
8 2 N 6.950 1.00820
9 21 E 9.670 9.41780
10 21 N 10.535 2.44205
11 22 E 7.720 2.04020
12 22 N 7.930 1.21680
13 24 E 9.555 10.35125
14 24 N 9.330 0.38720
15 25 E 8.240 0.92480
16 25 N 9.485 0.00125
17 27 E 8.635 0.08405
18 27 N 7.745 3.72645
19 28 E 9.635 8.61125
20 28 N 8.315 10.35125
21 3 E 6.005 7.72245
22 3 N 11.435 55.44045
23 31 E 9.590 9.94580
24 31 N 10.570 16.70420
25 35 E 9.055 0.32805
26 35 N 9.925 14.41845
27 36 E 9.040 2.08080
28 36 N 7.395 1.14005
29 5 E 8.430 3.38000
30 5 N 17.385 139.94645
31 6 E 6.930 0.24500
32 6 N 8.330 1.72980
33 7 E 10.650 0.23120
34 7 N 7.375 0.09245
35 9 E 8.885 7.56605
36 9 N 8.405 0.73205
Model with "Assignment" (algorithm).
> lmer(AUChr~Assignment+(1|RN),data=data1,REML=FALSE)
Linear mixed model fit by maximum likelihood
Formula: AUChr ~ Assignment + (1 | RN)
Data: data1
AIC BIC logLik deviance REMLdev
365.7 374.8 -178.8 357.7 356.9
Random effects:
Groups Name Variance Std.Dev.
RN (Intercept) 0.0000 0.0000
Residual 8.4152 2.9009
Number of obs: 72, groups: RN, 18
Fixed effects:
Estimate Std. Error t value
(Intercept) 8.7703 0.4835 18.14
AssignmentN 0.5131 0.6837 0.75
Correlation of Fixed Effects:
(Intr)
AssignmentN -0.707
Model without the algorithm variable.
> lmer(AUChr~(1|RN),data=data1,REML=FALSE)
Linear mixed model fit by maximum likelihood
Formula: AUChr ~ (1 | RN)
Data: data1
AIC BIC logLik deviance REMLdev
364.3 371.1 -179.1 358.3 358.5
Random effects:
Groups Name Variance Std.Dev.
RN (Intercept) 0.000 0.0000
Residual 8.481 2.9122
Number of obs: 72, groups: RN, 18
Fixed effects:
Estimate Std. Error t value
(Intercept) 9.0268 0.3432 26.3
>
> sessionInfo()
R version 2.11.1 Patched (2010-07-21 r52598)
Platform: i686-pc-linux-gnu (32-bit)
locale:
[1] LC_CTYPE=en_US LC_NUMERIC=C LC_TIME=en_US
[4] LC_COLLATE=C LC_MONETARY=C LC_MESSAGES=en_US
[7] LC_PAPER=en_US LC_NAME=C LC_ADDRESS=C
[10] LC_TELEPHONE=C LC_MEASUREMENT=en_US LC_IDENTIFICATION=C
attached base packages:
[1] stats graphics grDevices utils datasets methods base
other attached packages:
[1] lme4_0.999375-34 Matrix_0.999375-42 lattice_0.18-8
loaded via a namespace (and not attached):
[1] grid_2.11.1 nlme_3.1-96 stats4_2.11.1
>
> proc.time()
user system elapsed
3.488 0.056 3.536
--
Kevin E. Thorpe
Biostatistician/Trialist, Knowledge Translation Program
Assistant Professor, Dalla Lana School of Public Health
University of Toronto
email: kevin.thorpe at utoronto.ca Tel: 416.864.5776 Fax: 416.864.3016
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