[R-meta] multiple correlation meta-analysis as in Cheung & Chan (2002)

Mike Cheung m|kew|cheung @end|ng |rom gm@||@com
Sun Jan 15 04:13:10 CET 2023

Dear Catia,

I see.It was written by Shu Fai Cheung, not Mike Cheung.


On Sun, Jan 15, 2023 at 10:50 AM Catia Oliveira <catia.oliveira using york.ac.uk>

> I'm referring to the paper with Chan from 2000, this is an unpublished
> paper. I indicated the wrong date in the title.
> On Sun, Jan 15, 2023, 2:43 AM Mike Cheung <mikewlcheung using gmail.com> wrote:
>> Dear Catia,
>> I am afraid I did not get your questions, as something was wrong here.
>> The study you mentioned neither used multiple correlations as the effect
>> sizes nor Hunter and Schmidt's approach. It used correlation matrices as
>> inputs to fit a customized meta-analytic structural equation modeling
>> (MASEM) to handle interactions.
>> The complete data and R code are available at https://osf.io/3w2k7/ for
>> reproducibility.
>> Best,
>> Mike
>> On Thu, Jan 12, 2023 at 10:47 PM Catia Oliveira <
>> catia.oliveira using york.ac.uk> wrote:
>>> Hello,
>>> I am interested in running a similar study to that conducted by Mike
>>> Cheung (The role of perceived behavioral control in predicting human
>>> behavior: A
>>> meta-analytic review of studies on the theory of planned behavior)
>>> where the multiple correlations estimates (square root of R2) were
>>> tracked to determine whether a set of predictors have explanatory
>>> power when one has been accounted for. This will be done across
>>> datasets, so I would have to pool all the multiple correlations
>>> estimates using the same variables (e.g. all studies with 2 predictors
>>> X ~ A + B and all studies with 3 predictors X ~ A + B + C). Could I
>>> still use the Hunter and Schmidt approach used by Mike Cheung to
>>> aggregate the multiple correlations estimates? If so, how can I then
>>> compare the size of the R2 based on the number of predictors (e.g., is
>>> the multiple correlations estimates for 3 predictors sig higher than
>>> for 2)?
>>> Thank you,
>>> Catia
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