[R-SIG-Mac] Sorting each column of a matrix independently

[Ken Beath]

This question should be directed to R-Help

Anyway, sorted <- apply(unsorted,2,sort) should do it.

Ken

On 14/10/2010, at 7:06 PM, Desmond Lim wrote:

> Hi,
> 
> I have this matrix
> 
> unsorted$A with 5 columns (all numeric).
> 
> Currently I'm sorting the columns like this:
> 
> sorted$A[,1] <- sort(unsorted$A[,1])
> sorted$A[,2] <- sort(unsorted$A[,2]) ...
> 
> I have tried doing
> 
> sorted$A <- unsorted$A[do.call(order, data.frame(unsorted$A)),] but it
> sorts the first column then the 2nd column which it ties to the 1st
> column, then the 3rd which is tied to the 2nd, etc. I need all the
> columns to be independently sorted.
> 
> Any help is appreciated.
> 
> Desmond
> 
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