[R-sig-Geo] pretty in spplot()

[ONKELINX, Thierry]

Dear Tord,

You need to supply the datavalues to the pretty function. An untested example as your example was not reproducible with a (dummy) dataset.

PrettyBreaks <- pretty(as.vector(resdf[,c("TempEst.t","TempEst.tM1")]))
spplot(SpatialPolygonsDataFrame(karta, as.data.frame(resdf[,c("TempEst.t","TempEst.tM1")])),at=PrettyBreaks)

HTH,

Thierry

----------------------------------------------------------------------------
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and Forest
Cel biometrie, methodologie en kwaliteitszorg / Section biometrics, methodology and quality assurance
Gaverstraat 4
9500 Geraardsbergen
Belgium 
tel. + 32 54/436 185
Thierry.Onkelinx at inbo.be 
www.inbo.be 

To call in the statistician after the experiment is done may be no more than asking him to perform a post-mortem examination: he may be able to say what the experiment died of.
~ Sir Ronald Aylmer Fisher

The plural of anecdote is not data.
~ Roger Brinner

The combination of some data and an aching desire for an answer does not ensure that a reasonable answer can be extracted from a given body of data.
~ John Tukey

-----Oorspronkelijk bericht-----
Van: r-sig-geo-bounces at stat.math.ethz.ch [mailto:r-sig-geo-bounces at stat.math.ethz.ch] Namens Tord Snäll
Verzonden: vrijdag 14 november 2008 12:14
Aan: r-sig-geo at stat.math.ethz.ch
Onderwerp: [R-sig-Geo] pretty in spplot()

Dear all,
I would like legend cut-offs that are prettier that just executing
spplot(SpatialPolygonsDataFrame(karta, 
as.data.frame(resdf[,c("TempEst.t","TempEst.tM1")])))

I try
spplot(SpatialPolygonsDataFrame(karta, 
as.data.frame(resdf[,c("TempEst.t","TempEst.tM1")])),at=pretty())
, though without sucess.

Could someone give a clue on how to do it?

Thanks!

/Tord

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