[R-SIG-Finance] Efficient CVaR Scenario Optimization for a Large number of Scenarios
Robert Harlow
rharlow86 at gmail.com
Fri Feb 17 02:00:33 CET 2012
Great- Thanks again for all of your help
On Feb 16, 2012, at 12:55 PM, alexios ghalanos <alexios at 4dscape.com> wrote:
> Not sure but this sounds to me like the Lower Partial Moment problem (but i could be mistaken)...if it is, you should read up on the literature on this measure as it has been extensively covered (for the problem of the partial moment to the power 1 there is an LP representation, for the power 2 a QP representation, and for the rest or general LPM problem you can definitely represent it as a proper NLP).
>
> Regards,
> Alexios
>
> On 16/02/2012 15:55, Robert Harlow wrote:
>> Alexios,
>> I have one more question on this topic. With CVaR, one generally
>> knows the percentile, and then has to find the quantile that that
>> percentile corresponds to (VaR). Suppose that my objective function is
>> slightly different. In the following case, I have a fixed hurdle
>> return, and I would like to minimize the average return that is less
>> than that hurdle return multiplied by the likelihood of having a return
>> that is lower than the hurdle. Basically, this is just the expected
>> value of the return from -Inf to the hurdle (rather than -Inf to
>> positive Inf for the total expected value). This seems like it should
>> be an easier problem to solve than the CVaR one, but for some reason I
>> find it difficult. Is there a better way to write my objective function
>> (cvarStar) such that it nicely follows the process you already laid out
>> in the CVaR case?
>> Thanks again,
>> -Bob
>>
>> library(mvtnorm)
>> mu <- c(.04, .06, .1)
>> sig <- c(.04, .09, .2)
>> cor.mat <- rbind(c( 1, .6, .2),
>> c(.6, 1, .1),
>> c(.2, .1, 1)
>> )
>> v.cov <- sig%o%sig*cor.mat
>> set.seed(100)
>> n <- 1000
>> samps <- rmvnorm(n, mean = mu, sigma = v.cov)
>> cvarStar <- function(w, samps, hurd){
>> z <- samps %*%w
>> tail.v <- z[z<=hurd]
>> if(length(tail.v) == 0) tail.v <- 0
>> -(length(tail.v)/length(z))*mean(tail.v)
>> }
>> cvarStar(rep(1/3,3), samps, -.05)
>>
>> On Wed, Feb 15, 2012 at 6:01 PM, Robert Harlow <rharlow86 at gmail.com
>> <mailto:rharlow86 at gmail.com>> wrote:
>>
>> Wow, this is fantastic Alexios. Thank you very much.
>> -Bob
>>
>>
>> On Wed, Feb 15, 2012 at 5:11 PM, alexios <alexios at 4dscape.com
>> <mailto:alexios at 4dscape.com>> wrote:
>>
>> Hi Bob,
>>
>> There is a way to work with nonlinear solvers to solve this type
>> of problem (without resorting to expensive global optimization
>> approaches), once you work out the derivatives and decide on how
>> to deal with the min/max type functions so that the problem is
>> 'made convex'.
>>
>> A complete example follows:
>>
>> # We work with a smooth approximation to the max function:
>> epsilon = 1e-8
>>
>> .max.smooth = function(x)
>> {
>> (sqrt(x*x + epsilon ) + x) / 2
>> }
>>
>> # the objective function (CVaR)
>> func.cvar = function(w, Data, alpha, mu, rmin)
>> {
>> # we reverse the sign since we are minimizing
>> -w[1] + mean( .max.smooth(w[1] - Data %*% w[-1]) )/alpha
>> }
>>
>> # the gradient of the objective function
>> grad.cvar = function(w, Data, alpha, mu, rmin)
>> {
>> epsilon2 = epsilon^2
>> m = length(w)
>> N = dim(Data)[1]
>> g = vector(mode = "numeric", length = m)
>> port = Data %*% w[-1]
>> # first the derivative wrt to VaR
>> g[1] = ( sum( ( port - w[1] )/( 2*N * sqrt( epsilon2 + (
>> port - w[1] )^2 ) ) ) - 0.5 )/alpha + 1
>> for(i in 2:m){
>> g[i] = ( sum(Data[,i-1]/(2*N)) - sum(
>> (Data[,i-1] * ( port - w[1]) )/( ( 2*N ) * (epsilon2 + ( port -
>> w[1] )^2 )^0.5 ) ) )/alpha
>> }
>> # reverse the sign since we are minimizing
>> return(-1 * g)
>> }
>>
>> # the budget constraint:
>> func.eq = function(w, Data, alpha, mu, rmin){
>> sum(w[-1]) - 1
>> }
>> # gradient of equality
>> grad.eq = function(w, Data, alpha, mu, rmin){
>> m = length(w)-1
>> return( matrix(c(0, rep(1, m)), ncol = m+1, nrow = 1) )
>> }
>>
>> # Your inequality (weighted forecast >= rmin)
>> # but the solver we will use, sets: g(x) <= 0
>> # so we set: (rmin - weighted forecast) <= 0
>> func.ineq = function(w, Data, alpha, mu, rmin){
>> wM = sum( mu * w[-1] )
>> return( rmin - wM )
>> }
>> # gradient inequality
>> grad.ineq = function(w, Data, alpha, mu, rmin){
>> m = length(w)
>> Mu = matrix( c(0, mu), ncol = m )
>> return(-Mu)
>> }
>>
>>
>> ## Main Program Example (replicating your data)
>>
>> library(mvtnorm)
>> mu <- c(.04, .06, .1)
>> sig <- c(.04, .09, .2)
>> cor.mat <- rbind(c( 1, .6, .2),
>> c(.6, 1, .1),
>> c(.2, .1, 1)
>> )
>> v.cov <- sig%o%sig*cor.mat
>> set.seed(100)
>> n <- 10000
>>
>> samps <- rmvnorm(n, mean = mu, sigma = v.cov)
>> rmin = .08
>> alpha = 0.05
>> wmin = 0
>> wmax = 1
>>
>> # I am going to use the nloptr solver (get it from CRAN)
>> library(nloptr)
>>
>> .slsqp.ctrl = function(control = list())
>> {
>> ctrl = list()
>> ctrl$algorithm = "NLOPT_LD_SLSQP"
>> if( is.null(control$ftol_rel) ) ctrl$ftol_rel = 1e-12
>> else ctrl$ftol_rel = control$ftol_rel
>> if( is.null(control$xtol_rel) ) ctrl$xtol_rel = 1e-10
>> else ctrl$xtol_rel = control$xtol_rel
>> if( is.null(control$maxeval) ) ctrl$maxeval = 5000 else
>> ctrl$maxeval = as.integer( control$maxeval )
>> if( is.null(control$maxtime) ) ctrl$maxtime = 10000 else
>> ctrl$maxtime = control$maxtime
>> if( is.null(control$print_level) ) ctrl$print_level =0
>> else ctrl$print_level = as.integer( control$print_level )
>> if( is.null(control$local_opts$__algorithm) )
>> ctrl$local_opts$algorithm = "NLOPT_LD_MMA"
>> if( is.null(control$local_opts$__ftol_rel) )
>> ctrl$local_opts$ftol_rel = 1e-12 else ctrl$local_opts$ftol_rel
>> = control$local_opts$ftol_rel
>> if( is.null(control$local_opts$__xtol_rel) )
>> ctrl$local_opts$xtol_rel = 1e-10 else ctrl$local_opts$xtol_rel
>> = control$local_opts$xtol_rel
>> if( is.null(control$local_opts$__print_level) )
>> ctrl$local_opts$print_level = 0 else
>> ctrl$local_opts$print_level = as.integer(
>> control$local_opts$print_level )
>> return(ctrl)
>> }
>>
>> # set control parameters and subsolvers (use SQP)
>> ctrl = .slsqp.ctrl(control = list())
>>
>> # set starting values
>> q1 = quantile(samps %*% rep(1/3,3), alpha)
>> # we are estimating [VaR AND the weights]
>> sol = nloptr(
>> x0 = c(q1,rep(1/3,3)),
>> eval_f = func.cvar,
>> eval_grad_f = grad.cvar,
>> lb = c(-1, rep( wmin, 3) ),
>> ub = c( 0, rep( wmax, 3) ),
>> opts = ctrl,
>> eval_g_ineq = func.ineq,
>> eval_jac_g_ineq = grad.ineq,
>> eval_g_eq = func.eq,
>> eval_jac_g_eq = grad.eq,
>> Data = samps, alpha = 0.05, mu = colMeans(samps), rmin = 0.08)
>>
>> # [VaR w1 w2 w3]
>> # nloptr[-0.1125099 1.104523e-14 0.480181 0.519819]
>> # glpk[0.1125283 0.000000 0.480181 0.519819]
>> # end example
>>
>> HTH.
>>
>> Regards,
>>
>> Alexios
>>
>>
>>
>>
>>
>> On 15/02/2012 21:05, Robert Harlow wrote:
>>
>> Hi,
>> I am running into a memory issue when I try to run a
>> mean-CVaR
>> optimization on a large number of scenarios. I am running R
>> 32-bit on
>> windows (see sessionInfo() output below). I have attached
>> code to display
>> the problem below (using a sample from a random
>> multi-variate normal
>> distribution as an example, though that is not what I am
>> actually doing.)
>> I am using the methodology proposed by Uryasev (thanks to
>> Guy Yollin for
>> the cvarOpt function) to formulate the problem as an LP.
>> When I have a
>> small number of asset classes, I can arrive at good (though
>> sometimes non
>> "optimal" for a given set of scenarios) solutions using
>> different
>> optimizers (DEoptim, BBoptim, Rsolnp) where I don't run into
>> the scenario
>> size constraint. However, when I increase the number of
>> asset classes, the
>> non-LP solvers do a worse and worse job of finding a stable
>> "global"
>> optimum, with the exception of DEoptim which will arrive at
>> a good
>> solution, but will take a very long time for, say, 25 asset
>> classes and
>> 10,000 scenarios. The LP, on the other hand, seems much
>> more sensitive to
>> number of scenarios than to the number of asset classes.
>> Thanks in advance,
>> -Bob
>>
>> ## Code
>> library(Rglpk)
>> library(mvtnorm)
>> mu<- c(.04, .06, .1)
>> sig<- c(.04, .09, .2)
>> cor.mat<- rbind(c( 1, .6, .2),
>> c(.6, 1, .1),
>> c(.2, .1, 1)
>> )
>> v.cov<- sig%o%sig*cor.mat
>> set.seed(100)
>> n<- 1000 ##works
>> n<- 10000##doesn't work due to memory error
>> samps<- rmvnorm(n, mean = mu, sigma = v.cov)
>> cvarOpt<- function(rmat, alpha = .05, rmin = .05, wmin = 0,
>> wmax = 1,
>> weight.sum =1){
>> nAss = ncol(rmat) # number of assets
>> s = nrow(rmat) # number of scenarios i.e. periods
>> averet = colMeans(rmat)
>> ##create objective vector, constraint matrix,
>> constraint rhs
>> Amat =
>> rbind(cbind(rbind(1,averet),__matrix(data=0,nrow=2,ncol=s+1)__),cbind(rmat,diag(s),1))
>>
>> objL = c(rep(0,nAss), rep(-1/(alpha*s), s), -1)
>> bvec = c(weight.sum,rmin,rep(0,s))
>> ##direction vector
>> dir.vec = c("==",">=",rep(">=",s))
>> ##bounds on weights
>> bounds = list(lower = list(ind = 1:nAss, val =
>> rep(wmin,nAss)),upper =
>> list(ind = 1:nAss, val = rep(wmax,nAss)))
>> res = Rglpk_solve_LP(obj=objL, mat=Amat, dir=dir.vec,
>> rhs=bvec,
>> types=rep("C",length(objL)), max=T, bounds=bounds)
>> w = as.numeric(res$solution[1:__nAss])
>> return(list(w=w,status=res$__status))
>> }
>> ans.cvar<- cvarOpt(rmat = samps, rmin = .08)
>>
>> ## session info
>>
>> R version 2.13.2 (2011-09-30)
>> Platform: i386-pc-mingw32/i386 (32-bit)
>>
>> locale:
>> [1] LC_COLLATE=English_United States.1252
>> [2] LC_CTYPE=English_United States.1252
>> [3] LC_MONETARY=English_United States.1252
>> [4] LC_NUMERIC=C
>> [5] LC_TIME=English_United States.1252
>>
>> attached base packages:
>> [1] stats graphics grDevices utils datasets
>> methods base
>>
>> other attached packages:
>> [1] mvtnorm_0.9-9991 Rglpk_0.3-5 slam_0.1-22
>>
>> loaded via a namespace (and not attached):
>> [1] tools_2.13.2
>>
>> [[alternative HTML version deleted]]
>>
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